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3 years ago

6

Omar measured 5/8 pound of flour on a scale. He removed some flour from the scale so that only 3/16 pound was left. How much flo

ur did he remove?

1 answer:

RSB [31]3 years ago

3 0

Answer:

7/16

Step-by-step explanation:

5/8-3/16=7/16

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s344n2d4d5 [400]

➽━━━━━━━━━━━━━──➸

☺ Hello mate__ ❤

◾◾here is your answer...

i think right question is this

(3x − 7y)^2

ok now start solving:-

(3x − 7y)^2

=> (3x − 7y) (3x − 7y)

=> 3x(3x- 7y) -7y(3x-7y)

=>. 3x.3x - 3x.7y-7y. 3x + 7y.7y

=> 9x^2 -27xy +27xy + 49y^2

=> 9x^2 + 49y^2

so your correct ans. is 9x2 + 49y2

➽━━━━━━━━━━━━━──➸

I hope, this will help you.☺

Thank you______❤

✿┅═══❁✿ Be Brainly✿❁═══┅✿

7 0

4 years ago

viktelen [127]

Domain: x>0.

$(\log_2x)^2+7\log_2x+12=0$

Substitute $t=\log_2x\in\mathbb{R}$ . We have:

$t^2+7t+12=0\\\\a=1\qquad b=7\qquad c=12\\\\\\\Delta=b^2-4ac=7^2-4\cdot1\cdot12=49-48=1\\\\\sqrt{\Delta}=\sqrt{1}=1\\\\\\
t_1=\dfrac{-b-\sqrt{\Delta}}{2a}=\dfrac{-7-1}{2}=\dfrac{-8}{2}=-4\\\\\\
t_2=\dfrac{-b+\sqrt{\Delta}}{2a}=\dfrac{-7+1}{2}=\dfrac{-6}{2}=-3$

For t₁ there will be:

$\log_2x=t_1\\\\\log_2x=-4\\\\2^{-4}=x\\\\x=\dfrac{1}{2^4}\\\\\\x=\dfrac{1}{16}=0,0625\\\\\\\boxed{x\approx0,063}$

and for t₂:

$\log_2x=t_2\\\\\log_2x=-3\\\\2^{-3}=x\\\\x=\dfrac{1}{2^3}\\\\\\x=\dfrac{1}{8}\\\\\\\boxed{x=0,125}$

Answer d)

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svet-max [94.6K]

6 is correct for this questions answer

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Henry is putting money into a checking account. Let y represent the total amount of money in the account (in dollars). Let x rep

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20. In the image, ABC has measure 58°. What is the measure of ABD?

PolarNik [594]

Answer:

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Step-by-step explanation:

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