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soldier1979 [14.2K]
3 years ago
5

Circle WX = xy 2x+16, xw 7x-29 find wx

Mathematics
1 answer:
sweet [91]3 years ago
5 0

Answer:

WX=36

Step-by-step explanation:

2x+16=7x-29

45=5x

x=9

7x-29

7(9)-29

65-29

36

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Answer:

6^3=6×6×6=216. So, the answer is 6x6x6 and 216.

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A jar contains 3 red marbles, 2 blue marbles, and 5 yellow marbles. What is the
Mariana [72]

Answer:

1/10

Step-by-step explanation:

7 0
2 years ago
7(2x-5)=21<br><br> What is x?
Over [174]

Answer:

x = 4

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

Step-by-step explanation:

<u>Step 1: Define Equation</u>

7(2x - 5) = 21

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Distribute 7:                   2x - 5 = 3
  2. Isolate <em>x</em> term:                2x = 8
  3. Isolate <em>x</em>:                         x = 4

<u>Step 3: Check</u>

<em>Plug in x into the original equation to verify it's a solution.</em>

  1. Substitute in <em>x</em>:                  7(2(4) - 5) = 21
  2. Multiply:                             7(8 - 5) = 21
  3. Subtract:                            7(3) = 21
  4. Multiply:                             21 = 21

Here we see that 21 does indeed equal 21.

∴ x = 4 is the solution to the equation.

6 0
2 years ago
You are studying the relationship between the history of early childhood trauma (categorized as trauma/no trauma) and weight in
jeka57 [31]

Answer:

You can decide to <u>reject</u> the Null Hypothesis at p < 0.05.

Step-by-step explanation:

In this case, the relationship between the history of early childhood trauma and weight in adulthood are being studied.

The categories of childhood trauma are:

Trauma and No trauma.

So, number of rows is, <em>r</em> = 2.

The categories of weight in adulthood are:

Low to normal, Overweight, and Obese

So, number of columns is, <em>c</em> = 3.

The distribution of the statistic \chi^{2} is chi-square with (<em>r </em>- 1)(<em>c </em>- 1) degrees of freedom, where <em>r</em> represents the number of rows in the two-way table and <em>c</em> represents the number of columns.

Compute the degrees of freedom as follows:

df = (r-1)(c-1)=(2-1) \times (3-1) = 2

It is provided that the calculated value of Chi-square test statistic is 18.26.

Compute the <em>p</em>-value of the test as follows:

p-value=P(\chi^{2}_{2}\geq 18.26)\\=0.000108\\\approx0.00011

Decision rule:

The null hypothesis will be rejected if the <em>p</em>-value of the test is less than the significance level.

The significance level is, <em>α</em> = 0.05.

<em>p</em>-value = 0.00011 < <em>α</em> = 0.05.

The null hypothesis will be rejected at 5% level of significance.

Thus, the complete statement is:

"You can decide to <u>reject</u> the Null Hypothesis at p < 0.05."

4 0
3 years ago
I need sum help please and thanks :)
Leona [35]

Answer:

6/16n is your answer I think

4 0
3 years ago
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