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2 years ago

An isosceles triangle has base angles that each measure 52º. Which equation can be used to

Mathematics

1 answer:

VMariaS [17]2 years ago

5 0

Answer: I'm not the best at this but the answer that makes the most sense is B. 104+z=180

Step-by-step explanation: A triangle has 2 sides which are both 52 degrees. Add those to get 104 degrees. Now since a triangle has 3 sides we need to find the one other side so no answers with 2z match meaning the answer should be B.

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If figure 5 has 12 dots how many dots does figure 50 have

Katarina [22]

The answer is 600 dots

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2 years ago

20 people is only 4/5 of the total people....what is the total

sleet_krkn [62]

The total is 20*5/4=25

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2 years ago

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Complete the steps for x. <br> 5/6x- 1/5x =19 <br> 5/6x- 1/5x =19 <br> ?/30x=19

dybincka [34]

Answer:

x = 30

Step-by-step explanation:

5/6x- 1/5x =19

Get a common denominator of 30

5/6x * 5/5 - 1/5x * 6/6 = 19

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19/30x = 19

Multiply each side by 30/19

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2 years ago

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1 Given the data 21, 13, 13, 37, 13, 23, 25, 15:

insens350 [35]

A. the outlier is 37
B. the mean with the outlier is 20
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3 0

3 years ago

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If dy dx equals cosine squared of the quantity pi times y over 4 and y = 1 when x = 0, then find the value of x when y = 3.

Afina-wow [57]

Answer: $x = -\frac{8}{\pi}$

Explanation: Note that

$\frac{dy}{dx} = \cos^2 \left ( \frac{\pi y}{4} \right )
\\
\\ \frac{dy}{\cos^2 \left ( \frac{\pi y}{4} \right )} = dx
\\
\\ \int{\frac{dy}{\cos^2 \left ( \frac{\pi y}{4} \right )}} = \int dx
\\
\\ \boxed{x = \int{\sec^2 \left ( \frac{\pi y}{4} \right )dy}}$

To evaluate the integral in the boxed equation, let $u = \frac{\pi y}{4}$ . Then,

$du = \frac{\pi}{4} dy 
\\ \Rightarrow \boxed{dy = \frac{4}{\pi}du}$

So,

$x = \int{\sec^2 \left ( \frac{\pi y}{4} \right )dy}
\\
\\ = \int{\sec^2 u \left ( \frac{4}{\pi}du \right )}
\\
\\ = \frac{4}{\pi}\int{\sec^2 u du}
\\
\\ = \frac{4}{\pi} \tan u + C
\\
\\ \boxed{x = \frac{4}{\pi} \tan \left ( \frac{\pi y}{4} \right ) + C}\text{ (1)}$

Since y = 1 when x =0, equation (1) becomes

$0 = \frac{4}{\pi} \tan \left ( \frac{\pi (1)}{4} \right ) + C 
\\ 
\\ 0 = \frac{4}{\pi} (1) + C 
\\
\\ \frac{4}{\pi} + C = 0
\\
\\ \boxed{C = -\frac{4}{\pi}}$

With the value of C, equation (1) becomes

$\boxed{x = \frac{4}{\pi} \tan \left ( \frac{\pi y}{4} \right ) -\frac{4}{\pi} }$

Hence, if y = 3,

$x = \frac{4}{\pi} \tan \left ( \frac{\pi y}{4} \right ) -\frac{4}{\pi} 
\\
\\ x = \frac{4}{\pi} \tan \left ( \frac{\pi (3)}{4} \right ) -\frac{4}{\pi} 
\\
\\ x = \frac{4}{\pi} (-1) -\frac{4}{\pi} 
\\
\\ \boxed{x = -\frac{8}{\pi}}$

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3 years ago