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3 years ago

Find the zeros of the function below. -7x=x^2+12

Mathematics

1 answer:

Paul [167]3 years ago

5 0

Answer:

Step-by-step explanation:

-7x = x² + 12

Set equation to zero:

x² + 7x + 12 = 0

Quadratic formula:

x = [-7±√(7²-4·1·12)]/[2·1]

= [-7±√1]/2

= -3,-4

The zeros are -3 and -4

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If {x) = 3x + 2, what is (5)?

BigorU [14]

You mean f(x) = 3x+2 and what is f(5)?

f(5) = 3(5)+2

f(5) = 15+2

f(5) = 17

So f(5) = 17

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3 years ago

In a triangle, what is always opposite the angle that has the LEAST measure?

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Answer:

In any triangle: The shortest side is always opposite the smallest interior angle. The longest side is always opposite the largest interior angle.

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3 years ago

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Alenkinab [10]

Answer:

Option C is the correct answer.

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3 years ago

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4 years ago

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The base of a solid is the region in the first quadrant between the graph of y=x2 and the x -axis for 0≤x≤1 . For the solid, eac

nata0808 [166]

Answer:

The volume of the solid is π/40 cubic units.

Step-by-step explanation:

Please refer to the graph below.

Recall that the area of a semi-circle is given by:

$\displaystyle A=\frac{1}{2}\pi r^2$

The volume of the solid will be the integral from x = 0 to x = 1 of area A. Since the diameter is given by y, then the radius is y/2. Hence, the volume of the solid is:

$\displaystyle V=\int_0^1\frac{1}{2}\pi \left(\frac{y}{2}\right)^2\, dx$

Substitute:

$\displaystyle V=\frac{1}{2}\pi\int_0^1\left(\frac{x^2}{2}\right)^2\, dx$

Simplify:

$\displaystyle V=\frac{1}{2}\pi \int_0^1\frac{x^4}{4}\, dx$

Integrate:

$\displaystyle V=\frac{1}{2}\pi \left[\frac{x^5}{20}\Big|_0^1\right]$

Evaluate:

$\displaystyle V=\frac{\pi}{40}\left((1)^5-\left(0\right)^5\right)=\frac{\pi}{40}\text{ units}^3$

The volume of the solid is π/40 cubic units.

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3 years ago