Question

Find the zeros of the function below. -7x=x^2+12

Answer 1

Answer:

Step-by-step explanation:

-7x = x² + 12

Set equation to zero:

x² + 7x + 12 = 0

Quadratic formula:

x = [-7±√(7²-4·1·12)]/[2·1]

 =  [-7±√1]/2

 = -3,-4  

The zeros are -3 and -4