Find the zeros of the function below.
-7x=x^2+12
1 answer:
Answer:
Step-by-step explanation:
-7x = x² + 12
Set equation to zero:
x² + 7x + 12 = 0
Quadratic formula:
x = [-7±√(7²-4·1·12)]/[2·1]
= [-7±√1]/2
= -3,-4
The zeros are -3 and -4
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