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Juli2301 [7.4K]
2 years ago
13

Doug had been working 20 hours per week at a pet store for $8.00 per hour. His pay was increased to $8.50 per hour, and his hour

s were increased to 24 per week. His total weekly pay increase
Mathematics
1 answer:
stellarik [79]2 years ago
5 0

Answer:

$44

Step-by-step explanation:

First, find how much he was making originally:

Multiply the number of hours he worked by the amount he got per hour:

20(8)

= 160

Then, find how much he gets now:

24(8.50)

= 204

To find his total weekly pay increase, find the difference between them:

204 - 160

= 44

So, his total weekly pay increase is $44

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Bas_tet [7]

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The function touches the damping factor

at x=\frac{(4n-3)\pi}{2} and x=\frac{(4n-1)\pi}{2}

The x-intercept of f(x) is

at x=n\pi

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Given function is f(x)=e^{-3x} sin(x) and damping factor as y=e^{-3x} and y=(-1)e^{-3x}

To find when function touches the damping factor:

For f(x)=e^{-3x} sin(x) and y=e^{-3x}

Equating the both the equation,

e^{-3x} sin(x)=e^{-3x}

sin(x)=1

x=\frac{(4n-3)\pi}{2}

For f(x)=e^{-3x} sin(x) and y=(-1)e^{-3x}

Equating the both the equation,

e^{-3x} sin(x)=(-1)e^{-3x}

sin(x)=(-1)

x=\frac{(4n-1)\pi}{2}

Therefore, The function touches the damping factor x=\frac{(4n-3)\pi}{2} and x=\frac{(4n-1)\pi}{2}

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For x-intercept, y=0

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Hence, e^{-3x} is always greater than zero.

Therefore,sin(x)=0

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Thus,

The x-intercept of f(x) is at x=n\pi

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3 years ago
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