Answer:
The area of the shaded region is 125.664 square centimetre
Step-by-step explanation:
Area of the shaded region = area of the circle with radius 7 cm - area of the circle with radius 3 cm----------------(1)
<u>Step 1: Finding the area of the circle with radius 7 cm</u>
Area of the circle A = 
On substituting the value of the radius, we get
Area of the circle A =
Area of the circle A = 
square centimetre----------------(2)
<u>Step 2: Finding the area of the circle with radius 3 cm</u>
Area of the circle a =
On substituting the value of the radius, we get
Area of the circle a = 
Area of the circle a = 
square centimetre ----------------(3)
<u>Step 3: Finding the area of the shaded region</u>
Area of the shaded region = 
= 
= 125.664 square centimetre
Answer:
(0,1508)
Step-by-step explanation:
If X is years, and (x,y) is the format, and no years have passed for the first census, then 0 fills in for X and the number of people fills in for y.
Answer:
Q=(0.4.-1.7)
R=(2.4. 9.3)
S=(-10.6. 7.3)
Step-by-step explanation:
Just did it and got it wrong and these are the correct answers
9514 1404 393
Answer:
C. 3x∛(y²z)
Step-by-step explanation:
The relevant rules of exponents are ...
![\sqrt[n]{a^m} = a^\frac{m}{n}\\\\(a^b)^c=a^{bc}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%5Em%7D%20%3D%20a%5E%5Cfrac%7Bm%7D%7Bn%7D%5C%5C%5C%5C%28a%5Eb%29%5Ec%3Da%5E%7Bbc%7D)
__
Your expression can be rewritten and simplified as follows.
![\displaystyle\sqrt[3]{27x^3y^2z}=(3^3x^3y^2z)^\frac{1}{3}=3xy^\frac{2}{3}z^\frac{1}{3}=3x(y^2z)^\frac{1}{3}=\boxed{3x\sqrt[3]{y^2z}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Csqrt%5B3%5D%7B27x%5E3y%5E2z%7D%3D%283%5E3x%5E3y%5E2z%29%5E%5Cfrac%7B1%7D%7B3%7D%3D3xy%5E%5Cfrac%7B2%7D%7B3%7Dz%5E%5Cfrac%7B1%7D%7B3%7D%3D3x%28y%5E2z%29%5E%5Cfrac%7B1%7D%7B3%7D%3D%5Cboxed%7B3x%5Csqrt%5B3%5D%7By%5E2z%7D%7D)
We know that
A difference of two perfect squares (A² - B²) <span>can be factored into </span><span> (A+B) • (A-B)
</span> then
x ^4-4--------> (x²-2)*(x²+2)
(x²-2)--------> (x-√2)*(x+√2)
x1=+√2
x2=-√2
the other term
(x²+2)=0-> x²=-2-------------- x=(+-)√-2
i <span> is called the </span><span>imaginary unit. </span><span>It satisfies </span><span> i</span>²<span> =-1
</span><span>Both </span><span> i </span><span> and </span><span> -i </span><span> are the square roots of </span><span> -1
</span><span>√<span> -2 </span></span> =√<span> -1• 2 </span><span> = </span>√ -1 •√<span> 2 </span> =i • <span> √<span> 2 </span></span>
The equation has no real solutions. It has 2 imaginary, or complex solutions.
x3= 0 + √2<span> <span>i
</span></span>x4= 0 - √2<span> i </span>
the answer is
the values of x are
x1=+√2
x2=-√2
x3= 0 + √2 i
x4= 0 - √2 i
