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Talja [164]
3 years ago
7

Solve x - 12 = 7 using algebraic operations​

Mathematics
2 answers:
White raven [17]3 years ago
5 0

Answer:

19

Step-by-step explanation:

add 12 to both sides to get x = 19

12 + 12 = 0 since your getting rid of the constants and 12 + 7 = 19 so x = 19

Use the opposite operation in which its formed in

For example 3x = 18

you would have to multiply 3 by x right? So the opposite operation of that is divide by 3 since you dont know the value of x so do the known value which is the number 3 once you divide 18 by 3 you get 6 so put 6 on the right side and keep the equal sign between them to get x = 19.

Romashka [77]3 years ago
3 0

Answer:

19

Step-by-step explanation:

  1. Add 12 to each side: -12 + 12 = 0, 7 + 12 = 19

I hope this helps!

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the half-life of chromium-51 is 38 days. If the sample contained 510 grams. How much would remain after 1 year?​
madam [21]

Answer:

About 0.6548 grams will be remaining.  

Step-by-step explanation:

We can write an exponential function to model the situation. The standard exponential function is:

f(t)=a(r)^t

The original sample contained 510 grams. So, a = 510.

Each half-life, the amount decreases by half. So, r = 1/2.

For t, since one half-life occurs every 38 days, we can substitute t/38 for t, where t is the time in days.

Therefore, our function is:

\displaystyle f(t)=510\Big(\frac{1}{2}\Big)^{t/38}

One year has 365 days.

Therefore, the amount remaining after one year will be:

\displaystyle f(365)=510\Big(\frac{1}{2}\Big)^{365/38}\approx0.6548

About 0.6548 grams will be remaining.  

Alternatively, we can use the standard exponential growth/decay function modeled by:

f(t)=Ce^{kt}

The starting sample is 510. So, C = 510.

After one half-life (38 days), the remaining amount will be 255. Therefore:

255=510e^{38k}

Solving for k:

\displaystyle \frac{1}{2}=e^{38k}\Rightarrow k=\frac{1}{38}\ln\Big(\frac{1}{2}\Big)

Thus, our function is:

f(t)=510e^{t\ln(.5)/38}

Then after one year or 365 days, the amount remaining will be about:

f(365)=510e^{365\ln(.5)/38}\approx 0.6548

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The answer is D.

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Step-by-step explanation:

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3 years ago
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Can someone please help me with math.
Inessa05 [86]

4- 20

I created an equation for this one:

4x+x=100

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x=20

5. One pretzel costs $3

Create an equation:

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