Answer:
def newton(n):
#Define the variables.
t = 0.000001
esti = 1.0
#Calculate the square root
#using newton method.
while True:
esti = (esti + n / esti) / 2
dif = abs(n - esti ** 2)
if dif <= t:
break
#Return the result.
return esti
#Define the main function.
def main():
#Continue until user press enters.
while True:
try:
#Prompt the user for input.
n = int(input("Enter a number (Press Enter to stop):"))
#display the results.
print("newton = %0.15f" % newton(n))
except:
return
#Call the main function.
main()
Answer:
Learn OpenGL and any graphics rendering program.
Explanation:
I would vote for D since you can adjust picture positioning and wrapping. A is BS, B and C are not true.
Packet loss is typically resolved by time-outs and retries. For applications where a duplicate operation doesn't matter this is acceptable.
