Given:
A number is 400.
To find:
The additive inverse of 400.
Solution:
We know that the sum of a number and its additive inverse is 0.
If "a" is number and "b" is its additive inverse, then
Let x be the additive inverse of 400. Then,
Subtract both sides by 400.
Therefore, the additive inverse of 400 is 
.
16 is 40 because you just need to add 16 to 14 and to 10 which is equal 40
Answer:
L = 70
W = 32
Step-by-step explanation:
P = 2L + 2W
P 204 feet
W = x
L = 2x + 6
P = 2L + 2W
P = 2*(2x + 6) + 2*x
P = 4x + 12 + 2x
P = 6x + 12
But we know that P = 204 So 6x + 12 = 204
6x + 12 = 204 Subtract 12 from both sides
6x + 12 - 12 = 204 - 12 Collect like terms on the right
6x = 192 Divide by 6
x = 192/6
x = 32
Answer
W = 32
L = 2*W + 6
L = 2*32 + 6
L = 64 + 6
L = 70
You just multiply the top and bottom numbers like it was two normal multiplication problems. Ex. 3/4x1/4=3/16 (3x1,4x4) But its different because you have to put them together to make a fraction (3/16).
