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3 years ago

Please help me solve my problem!!!

Mathematics

1 answer:

77julia77 [94]3 years ago

8 0

Answer:

FH is the smallest angle since it is lesser than all the other ones.

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Please please help me with these questions. It’s urgent. I will mark BRAINLIEST.

zmey [24]

Answer:

$\large\boxed{Q1.\ \sin\theta=\dfrac{40}{41}}\\\boxed{Q2.\ 30^o}$

Step-by-step explanation:

Q1.

$\sin\theta=\dfrac{y}{r}$

$\text{We have}\\\\r=1\to(\text{radius of the unit circle}),\\\\y=\dfrac{40}{41}\to\text{from the given point}\ \left(\dfrac{9}{41},\ \dfrac{40}{41}\right)\\\\\text{Substitute:}\\\\\sin\theta=\dfrac{\frac{40}{41}}{1}=\dfrac{40}{41}$

Q2.

look at the picture

210° is in III Quadrant. Therefore the reference angle for θ is:

210° - 180° = 30°

8 0

3 years ago

X+2y-z = 9 -2x+y+z= 1 2x-y+2z= -5

hodyreva [135]

Answer:

I don't understand the first one

7 0

3 years ago

Please help! It would mean a lot and thanks! :)

notsponge [240]

To add 1/2 and 5/12, make both fractions have the same denominator:

1/2 is the same as 6/12, so 6/12+5/12=11/12

Thus, B is right.

7 0

3 years ago

The area of square is 350 CM square find the length of diagonal

grigory [225]

Step-by-step explanation:

hope this helps you.........

4 0

3 years ago

Read 2 more answers

PLz help with these questions. For questions 1 and 2 , write each expression using a single exponent. 1) x^9/x^2 2) h^14/h^5 F

Zepler [3.9K]

For questions 1 and 2 , write each expression using a single exponent.

$1) \ x^9:x^2=x^7\\
\\
2) \ h^{14}:h^{5}=h^9$

For questions 3 and 4, simplify each expression.

$3) \ 4^4:4^6=4^{-2}=\frac{1}{4^2}=\frac{1}{16}\\
\\
4) \ 5^0=1$

For questions 6-8, multiply the following polynomial.

$6) \ -2r(8r+5)=-16r^2-10r\\
\\
7) \ 4a(a^2+7a+4)=4a^3+28a^2+16a\\
\\
8) \ (2y-3)(3y-2)=6y^2-4y-9y+6=6y^2-13y+6$

4 0

3 years ago