<span>I believe for twelve (12) months.
Site A: $49.95 plus $59.40(4.95 x 12) equals $109.35
Site B: $9.95 x 12 equals $119.40
No, wait that's not right.
Okay, at 8 months, site A is pretty much at $90 (forget the nickels) and site B is $80 so site B is less.
At 7 months, site A is $85 and site B is $70 so site B is less.
At 9 months, site A is $95 and site B is $90 so site B is less.
At 10 months, site A $100 and site B is $100
It's got to be around 10 months somewhere.
Ten months would be $99.45 for site A and $99.50 for site B so B is less.
Eleven months is $104.40 for A and $109.45 for B so now B is more.</span>
I hope this helps you
y=f (x)=x-7
y=x-7
x=y+7
f^-1 (x)=x+7
Original polynomial:
2x^2 y + 8x^3 - xy^2 - 2x^3 + 3xy^2 + 6y^3
Order the polynomial in ascending order of y
8x^3 - 2x^3 + 2x^2y + 3xy^2 - xy^2 + 6y^3
Add up the similar terms:
6x^3 + 2x^2y + 2xy^2 + 6y^3
Thats is the polynomial Raj ended up with.
And the first term is 6x^3.
Answer: 6x^3
Answer: d = -16 .
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Explanation:
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Given: 0.2 (d − 6) = 0.3d + 5 − 3 + 0.1 d ; Solve for "d" ;
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→ Note the distributive property of multiplication:
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a (b + c) = ab + ac ;
a (b − c) = ab − ac ;
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As such, we can expand the left-hand side of the question:
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→ 0.2 (d − 6) = (0.2 *d) − (0.2 *6) = 0.2 d − 1.2;
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And rewrite the entire equation:
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→ 0.2 d − 1.2 = 0.3d + 5 − 3 + 0.1 d ;
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→ Let us multiply the ENTIRE equation (both sides) by "10"; to get rid of the decimals:
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→ 10 * {0.2 d − 1.2 = 0.3d + 5 − 3 + 0.1 d} ;
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→ 2d − 12 = 3d + 50 − 30 + 1d ;
→ Combine the "like terms", +3d , +1d ; to get 4d; on the 'right-hand side' of the equation ; and rewrite:
→ 2d − 12 = 4d + 50 − 30 ;
→ Now add "12"; and subtract "2d" from EACH SIDE of the equation;
→ 2d − 12 + 12 − 2d= 4d + 50 − 30 + 12 − 2d ;
→ 0 = 2d + 32 ; ↔ 2d + 32 = 0 ;
→ Subtract "32" from each side of the equation:
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→ 2d + 32 − 32 = 0 − 32 ;
→ 2d = - 32
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→ Now, divide EACH side of the equation by "2" ; to isolate "d" on ONE side of the equation; and to solve for "d" ;
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→ 2d / 2 = - 32 / 2 ;
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→ d = - 16 ; which is our answer.
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Let us check our answer by plugging this value for "d" in the original equation to see if the equation holds true when "d = -16" ;
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→ 0.2 (d − 6) = 0.3d + 5 − 3 + 0.1 d ;
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→ Let us start with the "left-hand side".
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→ 0.2 (d − 6) ; ↔ 0.2*(-16 − 6) ; ↔ 0.2*(-22) = -4.4.
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When "d" = -16 in the right-hand side of the equation,
is the result, "-4.4" ???
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→ 0.3d + 5 − 3 + 0.1 d = ? -4.4 ???
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→ (0.3 * -16) + 5 − 3 + (0.1 * -16) =? -4.4???
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→ (-4.8) + 5 − 3 + (-1.6) = ? -4.4????
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→ (-4.8) + 5 − 3 − (1.6) = ? -4.4????
→ -4.4 =? -4.4??? Yes!!!
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