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NISA [10]
3 years ago
14

2^24 x 3^2 x 1 hhhhhhhhhhhhhhhhhh

Mathematics
1 answer:
AysviL [449]3 years ago
6 0

Answer:

The answer is 5184. Hope it helps luv

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I dont know how to find x
AfilCa [17]

Answer:

not enough info, make another question with the problem attached

Step-by-step explanation:

7 0
2 years ago
Answer please lot's of points.
Svetlanka [38]

Answer:

t≈8.0927

Step-by-step explanation:

h(t) = -16t^2 + 128t +12

We want to find when h(t) is zero ( or when it hits the ground)

0 =  -16t^2 + 128t +12

Completing the square

Subtract 12 from each side

-12  =  -16t^2 + 128t

Divide each side by -16

-12/-16  =  -16/-16t^2 + 128/-16t

3/4 = t^2 -8t

Take the coefficient of t and divide it by 8

-8/2 = -4

Then square it

(-4) ^2 = 16

Add 16 to each side

16+3/4 = t^2 -8t+16

64/4 + 3/4= (t-4)^2

67/4 = (t-4)^2

Take the square root of each side

±sqrt(67/4) =sqrt( (t-4)^2)

±1/2sqrt(67) = (t-4)

Add 4 to each side

4 ±1/2sqrt(67) = t

The approximate values for t are

t≈-0.092676

t≈8.0927

The first is before the rocket is launched so the only valid answer is the second one

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3 years ago
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Elena L [17]
1/2x-2 is one answer
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2 years ago
The length of a rectangle is 3 inches more than twice its width, and its area is 65 square inches. What is the width?
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Width = 5 
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Subtract 6 from the x value in the first one, and remember that slope intercept form is mx+b
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