Answer:
95% confidence interval for the difference between the average mass of eggs in small and large nest is between a lower limit of 0.81 and an upper limit of 2.39.
Step-by-step explanation:
Confidence interval is given by mean +/- margin of error (E)
Eggs from small nest
Sample size (n1) = 60
Mean = 37.2
Sample variance = 24.7
Eggs from large nest
Sample size (n2) = 159
Mean = 35.6
Sample variance = 39
Pooled variance = [(60-1)24.7 + (159-1)39] ÷ (60+159-2) = 7619.3 ÷ 217 = 35.11
Standard deviation = sqrt(pooled variance) = sqrt(35.11) = 5.93
Difference in mean = 37.2 - 35.6 = 1.6
Degree of freedom = n1+n2 - 2 = 60+159-2 = 217
Confidence level = 95%
Critical value (t) corresponding to 217 degrees of freedom and 95% confidence level is 1.97132
E = t×sd/√(n1+n2) = 1.97132×5.93/√219 = 0.79
Lower limit = mean - E = 1.6 - 0.79 = 0.81
Upper limit = mean + E = 1.6 + 0.79 = 2.39
95% confidence interval for the difference in average mass is (0.81, 2.39)
Answer:
its going to be 2&3(x+2)(x+3)
Step-by-step explanation:
<span>
Not to worry, Anarkee, it's easy. They just dress it up in tech-speak.
What it means is "For what pair of numbers in the list is the statement
"Y = 6x" true, if the first number is x and the second is y".
You will notice that in every pair, one number is 6 times the other, but
if the numbers are arranged as ORDERED pairs, the convention is that x
comes before y. therefore only B, C and E satisfy the equation.
Simple but sneaky, huh? </span>
Answer:
235.980931
Step-by-step explanation:
Answer:
5 2/3
Step-by-step explanation:
I'm not sure how to explain, but 5 2/3 divided by itself is 1...
I hope this helped a little bit still. Have a great day c:
