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gayaneshka [121]

3 years ago

6

What is the difference between the circumference of a medium pizza and the circumference of a personal pizza? Round to the neare

st hundredth.

1 answer:

DanielleElmas [232]3 years ago

7 0

Answer:

?

Step-by-step explanation:

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10. The sum of two numbers is 6 less than twice the first number. Their difference is 10 less than four times the second number.

Ilya [14]

Answer:

10 and 4.

Step-by-step explanation:

Let x be the first number.

Let y be the second number.

x + y = 2x - 6

x - y = 4y - 10

x = 4y - 10 + y

x = 5y - 10

(5y - 10) + y = 2(5y - 10) - 6

6y - 10 = 10y - 20 - 6

6y - 10 = 10y - 26

6y - 10y = -26 + 10

-4y = -16

y = 4

x - (4) = 4(4) - 10

x - 4 = 16 - 10

x - 4 = 6

x = 6 + 4

x = 10

3 0

3 years ago

Please Help!!! :C

astraxan [27]

Answer:

10 ft

Step-by-step explanation:

Using the distance formula.

3 0

3 years ago

Use the quadratic formula to solve the equation. 2x2−6x+1=0 Enter your answers, in simplified radical form, in the boxes. x = or

kodGreya [7K]

To solve this problem you must apply the proccedure shown below:
1. You have the following quadratic equation given in the exercise above:
2x²−6x+1=0
2. The quadratic equation is:
x=[-b±√(b²-4ac)]/2a
Where:
a=2
b=-6
c=1
3. When you substitute these values into the quadratic equation, you obtain:
x=3/2-√(7)/2
x=3/2+√(7)/2

5 0

3 years ago

Read 2 more answers

The expression (1/50)(sqrt(1/50)+sqrt(2/50)+sqrt(3/50)+...+sqrt(50/50) is a Riemann Sum approximation for

alexira [117]

$\dfrac1{50}\left(\sqrt{\dfrac1{50}}+\sqrt{\dfrac2{50}}+\cdots+\sqrt{\dfrac{50}{50}}\right)=\displaystyle\sum_{n=1}^{50}\sqrt{\dfrac n{50}}\frac1{50}$

describes a sum of the areas of 50 rectangles, each of width $\dfrac1{50}$ , and the $n$ th rectangle has height $\sqrt{\dfrac n{50}}$ .

$\sqrt{\dfrac n{50}}$ ranges from a small positive number to 1, which means the integration interval must be $[0,1]$ . The sum is then the right-endpoint Riemann sum of $\sqrt x$ over the interval with $50$ equally spaced subintervals, so

$\displaystyle\sum_{n=1}^{50}\sqrt{\dfrac n{50}}\frac1{50}\approx\int_0^1\sqrt x\,\mathrm dx$

The sum itself evaluates to roughly 0.676, while the exact value of the integral is $\dfrac23\approx0.667$ .

3 0

3 years ago

Solve for the variable in the equations below. Round your answers to the nearest hundredth. Do not round any intermediate comput

Kobotan [32]

Answer:

Part 1) $x=-0.07$

Part 2) $y=2.48$

Step-by-step explanation:

Part 1) we have

$15^{-9x} =6$

Solve for x

Apply log both sides

$log(15^{-9x})=log(6)$

$-x*(9log(15))=log(6)$

$x=-log(6)/(9log(15))$

$x=-0.07$

Part 2) we have

$e^{y}=12$

Apply ln both sides

$ln(e^{y})=ln(12)$

$y*ln(e)=ln(12)$

Remember that

$ln(e)=1$

$y=ln(12)$

$y=2.48$

6 0

3 years ago

Read 2 more answers