Answer:
a) 18
b) 2.101
Step-by-step explanation:
a) What are the degrees of freedom for Student's t distribution when the sample size is 19?
Degrees of freedom = n - 1
Where n = sample size
= 19 - 1
= 18
b) Use the Student's t distribution to find tc for a 0.95 confidence level when the sample is 19.
(Round your answer to three decimal places.)
We would be determining these using the t distribution table
1 - 0.95 = 0.05 ( for two tailed)
Or
0.05/2 = 0.025(one - tailed)
Hence, the tc(test score) for a 0.95 confidence level when the sample is 19 is 2.101
