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3 years ago

Given: SV || TU and SVX = UTX

Mathematics

1 answer:

Vladimir [108]3 years ago

7 0

Answer: 2 is a given which is (SV | | TU)

I need help with the others.

Step-by-step explanation:

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Approximate (to the nearest hundredth) the missing length of the right triangle:

san4es73 [151]

Answer:

17.46

Step-by-step explanation:

c²=a²+b²

c²= 7²+16²

c = √ans

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3 years ago

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State the conclusion based on the results of the test. The standard deviationstandard deviation inin the pressure required to op

inysia [295]

Answer:

B. There is sufficient evidence that the mean of the pressure required to open a certain valve has changed.

Step-by-step explanation:

We make this conclusion based on these reasons:

We are told that the "null hypothesis was rejected" after the "manager feels that the pressure variability has changed., meaning the null hypothesis was the opposite of what occurred; that is to say, it is the alternate hypothesis that proved true instead.
"changes in the manufacturing process" form what can be called "sufficient evidence" that the mean of the pressure required to open the valve has changed, thereby going against the null hypothesis.

It is based on the above reasons that the null hypothesis was rejected.

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3 years ago

A store is having a sale where movies are 15% off their original price a movie is sale for $22.10 what was the original price of

Alexus [3.1K]

The original price of the movie would be $26. Hope this helps!

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3 years ago

Eliminate the parameter and obtain the standard form of the rectangular equation. Ellipse: x = h + a cos(θ), y = k + b sin(θ) Us

gayaneshka [121]

Answer:

a) $(\frac{x-h}{a})^2+ (\frac{y-k}{b})^2=1$

b) $x=1+5 \,cos(\theta)\,,\,y=4\,sin(\theta)$

c) $\frac{(x-1)^2}{25}+ \frac{y^2}{16}=1$

Step-by-step explanation:

Start by isolating the trigonometric expression in both equations, ad then use the Pythagorean identity:

$cos^2(\theta)+sin^2(\theta)=1$

to obtain the standard equation of a conic.

$x=h+a\,cos(\theta)\\x-h=a\,cos(\theta)\\cos(\theta)=\frac{x-h}{a}$ $y=k+b\,sin(\theta)\\y-k=b\,sin(\theta)\\sin(\theta)=\frac{y-k}{b}$

then:

$cos^2(\theta)+sin^2(\theta)=1\\(\frac{x-h}{a})^2+ (\frac{y-k}{b})^2=1$

this is the equation of an ellipse centered at (h,k), and with horizontal axis length = 2a , and vertical axis length = 2b.

The parametric equations are those we started with:

$x=h+a \,cos(\theta)\,,\,y=k+b\,sin(\theta)$ but we need to find the appropriate parameters for the requested ellipse, as shown below.

For an ellipse of vertices (-4,0) a,d (6,0) and foci at (-2,0) and (4.0), we are dealing with an ellipse with major horizontal axis on the line y=0, and major diameter length of 10 units, so the parameter $a=5$ . The center of the ellipse is therefore at (1,0).

We recall that the vertices of a translated horizontal ellipse are located at $(a+h,k)$ and $(-a+h,k)$ , then k=0 to satisfy the information given (-4,0) & (6,0), and since $a=5$ , we deduce that $a+h = 6$ and therefore h=1.

To find "b" (the only parameter missing for the standard equation of the conic), we need the information on the foci (-2,0) and (4,0) which must equal (h-c,k) and (h+c,k) with k=0 and h=1 which then gives that c=3

Now using the formula for the parameter "c" of the foci: $c=\sqrt{a^2-b^2}$

$c=\sqrt{a^2-b^2}\\3=\sqrt{5^2-b^2}\\9=25-b^2\\b^2=25-9\\b^2=16\\b=4$

Then we can write the equation of this ellipse in standard form as:

$(\frac{x-h}{a})^2+ (\frac{y-k}{b})^2=1\\(\frac{x-1}{5})^2+ (\frac{y-0}{4})^2=1\\\\(\frac{x-1}{5})^2+ (\frac{y}{4})^2=1\\\frac{(x-1)^2}{25}+ \frac{y^2}{16}=1$

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3 years ago

Subtract (-x+3)-(x-5)

KonstantinChe [14]

-x+3-x+5

-2x+8

-2(x-4) Answer

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3 years ago

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