You need to use the distance formula which is √(x2-x1)^2+(Y2-y1)^2
false
The limit as a definite integral on the interval
on [2π , 4π] is
.
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What is meant by definite integral?</h3>
A definite integral uses infinitesimal slivers or stripes of the region to calculate the area beneath a function. Integrals can be used to represent a region's (signed) area, the cumulative value of a function changing over time, or the amount of a substance given its density.
Definite integral, a term used in mathematics. is the region in the xy plane defined by the graph of f, the x-axis, and the lines x = a and x = b, where the area above the x-axis adds to the total and the area below the x-axis subtracts from the total.
If an antiderivative F exists for the interval [a, b], the definite integral of the function is the difference of the values at points a and b. The definite integral of any function can also be expressed as the limit of a sum.
Let the equation be

substitute the values in the above equation, we get
=
on [2π, 4π],
simplifying the above equation

To learn more about definite integral refer to:
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Answer:
The new point would be (-3,-6)
Step-by-step explanation:
To solve this it is nice to graph the first point at (1,-1). Then move the point left 4 units, making x -3. and then 5 units down, which would make y -6.
Answer:
40$,160$ & 60
Step-by-step explanation:
First,find the equation using y-y1/ y1-y2=x-x1=x1-x2
y-0/0-20=x-0/0-3
y=20x/3
Now put the values of x& y in the equation, for the 1st one,
y=20×6/3
=40
2nd one.y=20×24/3
=160
3rd one,
400=20x/3
X=400×3/20
=60