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o-na [289]
3 years ago
5

How do you calculate distance​

Mathematics
1 answer:
ValentinkaMS [17]3 years ago
8 0

Answer:

d = st,

Step-by-step explanation:

Distance= speed times rate

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(6)/(7)x-(2)/(5)y+(5)/(7)(y+x)<br> PLEASE HELP!!!!!
muminat

Answer:

55x + 11y/ 35

Step-by-step explanation:

7 0
3 years ago
Find the surface area of a cylinder the has a base radius of 2 feet and the height of 14 feet
Mashutka [201]

Answer: If I am correct the answer is 201.06ft²

please do correct me if i am wrong.

Step-by-step explanation:

A=2πrh+2πr2=2·π·2·14+2·π·22≈201.06193ft²

5 0
2 years ago
If you could please kindly help :D
BartSMP [9]

Answer:

y = -1/2 ( x − 4 )^2 + 8

Step-by-step explanation:

First find the vertex form

y = a ( x − h )^ 2 + k  where ( h,k) is the vertex

The vertex is  ( 4,8)

y = a ( x − 4 )^2 + 8

Now we need to determine a

Pick a point on the graph (0,0)

and substitute this point into the equation

0 = a ( 0 − 4 )^2 + 8

0 = a (16) +8

-8 = 16a

-8/16 =a

-1/2

y = -1/2 ( x − 4 )^2 + 8

7 0
3 years ago
A student has homework assignments in each of his five daily classes he estimates that each assignment will take 30 minutes to c
olga_2 [115]

Answer:

he has to start at 8:30 PM I think

Step-by-step explanation:

it's because you do 30*5 then you get the answer 150, then you will do 150/60 whitch will get you to 2.5 and I think 2.5 is 2 hours, and 30 minutes. Then you minius 2 hours, and 30 minutes to the 10 hours and you get 8:30 PM (I don't know if that's correct or not)

6 0
3 years ago
A rocket is launched straight up from the ground with an initial velocity of 192 feet per second. The equation for the height of
Ivenika [448]

The equation for the height of the rocket at time t given

h= -16t^2+192t

We have to find the time t, when the rocket reaches 560 feet.

That means we have to find t when h = 560 ft. we will place 560 in the place of h to find t now.

h= -16t^2+192t

560 = -16t^2+192t

In the right side, we can check -16 is the common factor. So we will take out -16 from the rigbht side.

560 = -16(t^2 - 12t)

To get rid of -16 from the right side and move it to left side, we will divide both sides by -16.

560/-16 = -16(t^2-12t)/-16

-35 = t^2 -12t

Now we will move -35 to the righ side by adding 35 to both sides.

-35+35 = t^2-12t+35

0 = t^2 -12t+35

t^2-12t+35 = 0

We will factorize thee left side to find the values of t now. We need to find a pair of factors of 35 that by adding them we will get -12.

The pair of factors of 35 are -5 and -7 and by adding -5-7 we will get -12.

t^2-12t+35 =0

(t-5)(t-7) =0

So by using zero product property we will get

t-5 =0

t-5+5 = 0+5

t=5

Also t-7 =0

t-7+7 = 0+7

t=7

So we have got the rocket reaches at 560ft when t = 5 seconds and also when t = 7 seconds.

Now part b.

When the rocket completes its trajectory and hits the ground then the height or h = 0. So we will place h = 0 there in the equation.

h= -16t^2+192t

0= -16t^2 + 192 t

0 = -16(t^2-12t)

-16(t^2-12t) = 0

We will move -16 to the other side by dividing it to both sides.

-16(t^2-12t)/-16 = 0/-16

t^2-12t = 0

We will take out the common factor t from the left side. By taking out t we will get,

t(t-12) = 0

We will use zero product property now. By using that we will get,

t = 0

ans also t-12 = 0

t-12+12 = 0+12

t = 12

When the rocket completes its trajectory and hits the ground the time t can not be 0. When t =0, the rocket starts the trajectory.

So when the rocket completes its trajectory and hits the ground ,

then t = 12seconds.

So we have got the required answers.

6 0
3 years ago
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