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klio [65]
3 years ago
8

Solve the compound inequality and give your answer in interval notation

Mathematics
1 answer:
frutty [35]3 years ago
7 0

Answer:

(-∞, -8) U [3, ∞)

Step-by-step explanation:

4x - 4 < -36   OR -2x -1 ≤ -7

4x < -32         OR  -2x ≤ -6

 x < -8            OR     x ≥ 3    *divide by a negative, switch inequality

      (-∞, -8) U [3, ∞)  

   

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Gavin and Ian go to the movie theater and purchase refreshments for their friends. Gavin spends a total of $80.00 on 6 drinks an
ruslelena [56]

Answer:

Answer: 8.00 for a bag of popcorn, drink: 4:00.

Step-by-step explanation:

Set up a system of equations, solve 6d+7b=80

2d+6b=56. Solve for b and d.


Hope this helps, if did rate 5 stars. Thanks.

8 0
3 years ago
What is 1.7 expressed as a fraction in simplest form?
monitta
Either I've made a miscalculation... or none of these are correct...

1.7 in it's simplest form is 17/10.
So... neither A, B, C, or D is correct.
4 0
4 years ago
Which equation represents the model shown below
Alona [7]

Answer:

-4x - 3 = -8

Step-by-step explanation:

On our left, we have -x in 4 places = 4(-x) = -4x

And on the left, we also have -1 in 3 places = 3(-1) = -3

Altogether in our left, we have: -4x +(-3)

That is: -4x - 3

On our right, we have -1 in 8 places, which is 8(-1) = -8

Therefore, the equation that represents the model would be:

-4x - 3 = -8

6 0
3 years ago
If z varies inversely as w^2, and z=10 when w=6, find z when w=2
Dmitry [639]

Answer:

90

Step-by-step explanation:

If z varies inversely as w^2 then:

z=k/(w^2)  

z=10 when w=6:

10=k/36---> k=360

z=k/2^2

z=360/4=90

4 0
4 years ago
Each side of a square is increasing at a rate of 5 cm/s. At what rate is the area of the square increasing when the area of the
icang [17]

Answer:

<h2>70cm/s</h2>

Step-by-step explanation:

Area of a square with side of length L is expressed as A = L². The rate at which the area is increasing will be expressed as dA/dt.

dA/dt = dA/dL * dL/dt where

dL/dt is the rate at which each side of the square is increasing.

Since dA/dL = 2L, dA/dt = 2L dL/dt

Given dL/dt = 5cm/s and the Area of the square = 49 cm²

49 = L²

L = √49

L = 7cm

dA/dt = 2(7) * 5

dA/dt = 14*5

dA/dt = 70cm/s

The rate at which the area of the square is increasing is 70cm/s

3 0
3 years ago
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