A paper popcorn cone measures 4 inches in a diameter and is 9 inches high?

Mathematics

2 answers:

Aloiza [94]3 years ago

8 0

Explanation is in the file

tinyurl.com/wtjfavyw

Salsk061 [2.6K]3 years ago

8 0

Answer:

Step-by-step explanation:

Bc I said

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You are building a model of a square pyramid. The side length of the base of the model is 30 cm. The height is 21 cm. What is th

Shalnov [3]

Answer:

Step-by-step explanation:

find the area of the base (square)=900 sq. cm
find area of triangles=1260 sq. cm
total= 2160 sq. cm

6 0

3 years ago

1,13, 19..<br> Arithmetic, geometric, or neither

rosijanka [135]

Answer:

Neither.

Step-by-step explanation:

13 - 1 = 12 and 19 - 13 = 6 - no common difference so its not Arithmetic.

13/1 = 13 and 19/13 = 1.46 - no common ratio so its not Geometric.

4 0

3 years ago

Find the equation of a line that is perpendicular to y = 3x – 5 and passes through the point (1, -3).

Svetradugi [14.3K]

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

$\begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}\qquad \qquad y = \stackrel{\stackrel{m}{\downarrow }}{3}x-5$

well then therefore

$\stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{3\implies \cfrac{3}{1}} ~\hfill \stackrel{reciprocal}{\cfrac{1}{3}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{1}{3}}}$

so we're really looking for the equation of a line with slope of -1/3 and that passes through (1, -3 )

$(\stackrel{x_1}{1}~,~\stackrel{y_1}{-3})\qquad \qquad \stackrel{slope}{m}\implies -\cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{-\cfrac{1}{3}}(x-\stackrel{x_1}{1})\implies y+3=-\cfrac{1}{3}x+\cfrac{1}{3} \\\\\\ y=-\cfrac{1}{3}x+\cfrac{1}{3}-3\implies y=-\cfrac{1}{3}x-\cfrac{8}{3}$