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chubhunter [2.5K]
3 years ago
7

What is the value of the expression -35.62/2.6 *

Mathematics
2 answers:
scoray [572]3 years ago
6 0

Answer:

-13.7

Step-by-step explanation:

Reduce the expression, if possible, by cancelling the common factors.

maria [59]3 years ago
3 0

Answer:

-13.7

Step-by-step explanation:

when you divide -35,62 by 2.6 you get -13.7

Done! Hope you learned how to do this/understood this and have a great day! Please mark me as brainliest, vote 5.0 on my answer and thank me to show some support! Bye!

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Tanzania [10]

Answer - I think the answer is 59

Step-by-step explanation:

6 0
3 years ago
Can anyone help me out?
Lana71 [14]

Answer:

3y= -42

y= -14

Step-by-step explanation:

3y= -42

-42/3= -14

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3 0
3 years ago
Suppose compact fluorescent light bulbs last, on average, 11,500 hours. The distribution is normal and the standard deviation is
juin [17]

Answer:

2.275%

Step-by-step explanation:

The first thing to do here is to calculate the z-score

Mathematically;

z-score = (x-mean)/SD

from the question, x = 12,300 hours , mean = 11,500 hours while Standard deviation(SD) = 400 hours

Plugging the values we have;

z-score = (12,300-11,500)/400 = 800/400 = 2

Now, we want to calculate P(z ≤ 2)

This is so because we are calculating within a particular value

To calculate this, we use the z-score table.

Mathematically;

P(z ≤ 2) = 1 - P(z > 2) = 1 - 0.97725 = 0.02275

To percentage = 2.275%

6 0
3 years ago
What is the reference angle for a 240 degree angle?
Veronika [31]
The reference angle for 240° is 60° because 240 is in quadrant III. If you were to subtract 240 from 180 you’d get 60.
5 0
2 years ago
What does 12(6-k) equal​
gregori [183]

\text{Hey there!}

\rightarrow\text{What does 12(6 - k) equal?}

\text{Well, the formula is: a(b + c) = a(b) + a(c) = ab + ac}

\bf{12( 6 - k) = 12(6) - 12(k)= \underline{72 -12k}}

\boxed{\boxed{\text{\bf{Thus, your answer is: 72 - 12k}}}}\checkmark

\text{Good luck on your assignment and enjoy your day!}

~\frak{LoveYourselfFirst:)}

8 0
3 years ago
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