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gtnhenbr [62]
3 years ago
11

Use equivalent ratios to find the unknown value. 2 The unknown value is

Mathematics
1 answer:
Travka [436]3 years ago
8 0

Answer:

Unknown number = 36

Step-by-step explanation:

Equivalent ratio means,

\frac{x_1}{y_1}=\frac{x_2}{y_2}

If x_1=2, y_1=9 and x_2=8,

\frac{2}{9}=\frac{8}{y_2}

By cross multiplication,

2 × y₂ = 8 × 9

2y₂ = 72

\frac{2y_2}{2}=\frac{72}{2}

y₂ = 36

Therefore, missing number in the denominator of the fraction will be 36.

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When Vince does 14 push-ups and 12 sit-ups, it takes a total of 52 seconds. In comparison, he needs 48 seconds to do 12 push-ups
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Answer:

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Step-by-step explanation:

14x + 12y = 52

12x + 12y = 48

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x stands for pushups

y stands for situps

if we subtract the second equation from the first, we get

2x = 4

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Two pools are being drained. To start, the first pool had 3850 liters of water and the second pool had 4370 liters of water. Wat
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Answer:

(a)

Amount of water in the first pool (in liters) = 3850 liters - 33 liters per minute * x minutes

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(b)

3850 liters - 33 liters per minute * x minutes= 4370 liters - 43 liters per minute * x minutes

Step-by-step explanation:

(a) With x being the minutes after which you want to calculate the amount of water in the pool, to calculate this amount of water you must subtract the water drained from the initial amount of water that the pool contains.

Knowing that, for example, the water from the first pool drains at a rate of 33 liters per minute, then after x minutes, the total water drained will be 33 liters per minute * x minutes. Then:

<u><em>Amount of water in the first pool (in liters) = 3850 liters - 33 liters per minute * x minutes</em></u>

Reasoning in the same way:

<u><em>Amount of water in the second pool (in liters) = 4370 liters - 43 liters per minute * x minutes</em></u>

(b)  Now want to know when the two pools would have the same amount of water.  If they have the same amount of water then you can express:

Amount of water in the first pool = Amount of water in the second pool

Replacing the expressions found in (a):

<u><em>3850 liters - 33 liters per minute * x minutes= 4370 liters - 43 liters per minute * x minutes</em></u>

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