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Bingel [31]
2 years ago
6

Find x...............................

Mathematics
2 answers:
Stolb23 [73]2 years ago
8 0
X=1

im sorry.. im not entirely sure but i just cross-multiplied so x/45 = 2/90 and so yeah I got 1
notsponge [240]2 years ago
6 0

Answer:

sqrt(2) =x

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

sin theta = opp/ hyp

sin 45 = x/2

2 sin 45 =x

2 ( sqrt(2)/2) =x

sqrt(2) =x

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The area of a square is 64 square units. How many units long is each of its sides?
skelet666 [1.2K]
<h2>Area of a square = side × side</h2>

Let the side = x

{x}^{2}  = 64 \\ x =  \sqrt{64}  \\ x = 8

<h3>Length of each side = <u>8</u><u> </u><u>units</u></h3>

.... Hope this will help....

3 0
2 years ago
Help and fast! pleaseeeeeeeee
AfilCa [17]

Answer:

7

Step-by-step explanation:

<h2><em><u>to</u></em><em><u> </u></em><em><u>smome</u></em><em><u> </u></em><em><u>in</u></em><em><u> </u></em><em><u>your</u></em><em><u> </u></em><em><u>body</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>difference</u></em><em><u> </u></em><em><u>between</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>difference</u></em><em><u> </u></em><em><u>between</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>person</u></em><em><u> </u></em><em><u>who</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>good</u></em><em><u> </u></em><em><u>thing</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>smome</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>few</u></em><em><u> </u></em><em><u>people</u></em><em><u> </u></em><em><u>are</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>different</u></em><em><u> </u></em><em><u>type</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>you</u></em><em><u> </u></em><em><u>are</u></em><em><u> </u></em><em><u>not</u></em><em><u> </u></em><em><u>sure</u></em><em><u> </u></em><em><u>how</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>make</u></em><em><u> </u></em><em><u>them</u></em><em><u> </u></em><em><u>better</u></em><em><u> </u></em><em><u>or</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>person</u></em><em><u> </u></em><em><u>with</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>better</u></em><em><u> </u></em><em><u>sense</u></em><em><u> </u></em><em><u>than</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>other</u></em><em><u> </u></em><em><u>person</u></em><em><u> </u></em><em><u>in</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>different</u></em><em><u> </u></em><em><u>type</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>you</u></em><em><u> </u></em><em><u>are</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>good</u></em><em><u> </u></em><em><u>relationship</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>difference</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>difference</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>difference</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>difference</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>that</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>answer</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>smome</u></em><em><u> </u></em></h2>
3 0
2 years ago
(10 points)What is the sum of the first ten terms of the sequence 4,-12, 36, -144...
MrRissso [65]

Answer:

b

Step-by-step explanation:

7 0
3 years ago
Solve the equation 6w2 – 7w – 20 = 0.
azamat

For this case we have the following quadratic equation:

6w ^ 2-7w-20 = 0

Where:

a = 6\\b = -7\\c = -20

Its roots will be given by:

w = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2 (a)}\\w = \frac {- (- 7) \pm \sqrt {(- 7) ^ 2-4 (6) (- 20)}} {2 (6)}\\w = \frac {7 \pm \sqrt {49 + 480}} {12}\\w = \frac {7 \pm \sqrt {529}} {12}\\w = \frac {7 \pm23} {12}

The roots are:

w_ {1} = \frac {7 + 23} {12} = \frac {30} {12} = \frac {15} {6} = \frac {5} {2}\\w_ {2} = \frac {7-23} {12} = \frac {-16} {12} = - \frac {8} {6} = - \frac {4} {3}

Answer:

w_ {1} = \frac {5} {2}\\w_ {2} = - \frac {4} {3}

7 0
3 years ago
Read 2 more answers
F(x) = 3x2 - 11<br> Find f(-5)
Over [174]
F(x)=3x2-11
f(5)=6-11
5f=-5
5f/5=-5/5
f=-1
6 0
3 years ago
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