300=x^2+15x what is x?

Mathematics

1 answer:

Vlada [557]3 years ago

6 0

Answer:

x = -26.3746, 11.3746

Step-by-step explanation:

Easiest and fastest way to solve for <em>x</em> is to graph x² + 15x - 300 and analyze where the graph crosses the x-axis.

Alternatively, you can use the Quadratic Formula to help solve for <em>x</em>.

You might be interested in

in one year dog's weigh from 64 pounds to 80 pounds . by what percentage did the dog's weght increase

Masja [62]

Answer:

15%

Step-by-step explanation:

First, let's find how many pounds the dog's weight increased by during the year.

80 - 64 = 16

Now, knowing that the dog's weight increased by 16 pounds, we can use that to figure out the percentage of 16 out of 64 (divide them, then multiply by 100 to get a percentage).

$\frac{16}{64}$ • 100 = 0.25 • 100 = 25%

8 0

3 years ago

A farmer has two pieces of land in a parallelogram shape on the same base. He grows vegetables and flowers in two triangular pie

Hitman42 [59]

Step-by-step explanation:

In trapezoid ABCF, AB || CF.

Therefore, parallelograms ABEF & ABCD have same height and lie on the same base AB.

$\therefore Ar(\parallel^{gm} ABEF) = Ar(\parallel^{gm}ABCD)\\... (1)\\\\ \because\: Ar(\parallel^{gm} ABEF) \\=Ar(\triangle AFD) + Ar(\square \: ABED)....(2) \\\\\&\: Ar(\parallel^{gm}ABCD)\\= Ar(\triangle BCE) +Ar(\square ABED)....(3)$

From equations (1), (2) & (3), we find:

$Ar(\triangle AFD) + Ar(\square \: ABED) \\ = Ar(\triangle BCE) +Ar(\square ABED) \\ \\ \purple {\boxed {\therefore Ar(\triangle AFD) = Ar(\triangle BCE)}} \\$