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Lerok [7]
3 years ago
15

I need help with this important question it's for a important grade​

Mathematics
1 answer:
Novay_Z [31]3 years ago
3 0

Answer:

50

Step-by-step explanation:

29+42+61+?=180

add (29,42,61) that gives you 132

now 132-180=48

48 rounded to the nearest tenth is 50 sooo....

X= 50

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Georgia [21]

Answer:

sorry

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8 0
3 years ago
For each $n \in \mathbb{N}$, let $A_n = [n] \times [n]$. Define $B = \bigcup_{n \in \mathbb{N}} A_n$. Does $B = \mathbb{N} \time
andre [41]

Answer:

No, it is not.

Step-by-step explanation:

The set C = \mathbb{N} \times \mathbb{N} contains every ordered pair of Natural numbers, while B only contains those pairs in which both values in each entry are the same. Therefore, C is a bigger set than B, but B is not equal to C because for example C contains [1] \times [2] and B doesnt because 1 is not equal to 2.

4 0
3 years ago
The ratio of girls to boys in he 6th grade is 6 to 7. How many girls are there if there are 364 total students
inn [45]

If the ratio is 6:7 the students should divide nicely into 6+7=13 parts.  Six of those parts are girls, seven of those parts are boys.

364 / 13 = 28

So 6 × 28 = 168 girls

Answer: 168

Check:

7 × 28 = 196 boys

168 + 196 = 364, good



4 0
3 years ago
Read 2 more answers
A group of retired admirals, generals, and other senior military leaders, recently published a report, "Too Fat to Fight". The r
weqwewe [10]

Answer:

z=\frac{0.694 -0.75}{\sqrt{\frac{0.75(1-0.75)}{180}}}=-1.735  

p_v =P(z  

If we compare the p value obtained and the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of americans between 17 to 24 that not qualify for the military is significantly less than 0.75 or 75% .  

Step-by-step explanation:

1) Data given and notation  

n=180 represent the random sample taken  

X=125 represent the number of americans between 17 to 24 that not qualify for the military

\hat p=\frac{125}{180}=0.694 estimated proportion of americans between 17 to 24 that not qualify for the military

p_o=0.75 is the value that we want to test  

\alpha=0.05 represent the significance level  

Confidence=95% or 0.95  

z would represent the statistic (variable of interest)  

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that less than 75% of Americans between the ages of 17 to 24 do not qualify for the military :  

Null hypothesis: p\geq 0.75  

Alternative hypothesis:p < 0.75  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.  

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.694 -0.75}{\sqrt{\frac{0.75(1-0.75)}{180}}}=-1.735  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(z  

If we compare the p value obtained and the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of americans between 17 to 24 that not qualify for the military is significantly less than 0.75 or 75% .  

6 0
3 years ago
Percent between 230.59 and 243.24
yaroslaw [1]
All we have to do here is subtract 243.24 from 230.59 to get our percentage.
243.24 - 230.59 = 12.65%
3 0
3 years ago
Read 2 more answers
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