All categories

2 years ago

I need help with this important question it's for a important grade

Mathematics

1 answer:

Novay_Z [31]2 years ago

3 0

Answer:

Step-by-step explanation:

29+42+61+?=180

add (29,42,61) that gives you 132

now 132-180=48

48 rounded to the nearest tenth is 50 sooo....

X= 50

You might be interested in

Write 6 17/20 as a decimal

djverab [1.8K]

Answer:

6.85

Step-by-step explanation:

6 17/20

Convert to improper fraction.

137/20

Divide.

= 6.85

3 0

3 years ago

Read 2 more answers

I don’t understand this question?

Andrej [43]

Answer:

no, because it has a constant rate of change

Step-by-step explanation:

this is because the x and y change at the same rate. non linear means that they dont change at the same rate.

5 0

3 years ago

Which is an equation of the line perpendicular to y = -3/4x + 1 and passes through (3, 4)?

topjm [15]

Answer:

Step-by-step explanation:

perp. 4/3

y - 4 = 4/3(x - 3)

y - 4 = 4/3x - 4

y = 4/3x

5 0

3 years ago

What is 2 2/15 - 1 2/3=<br> I ended up with 2 3/21 <br> Really need help with this!

QveST [7]

Answer:

$2 \frac{2}{15} - 1 \frac{2}{3}$

$= \frac{32}{15} - \frac{5}{3}$

$= \frac{32 \times 1 - 5 \times 5}{15}$

$= \frac{32 - 25}{15}$

$= \frac{7}{15}$

5 0

3 years ago

If, P(x,y) is a point on the unit circle determined by real number δ, then tanδ = what

Lisa [10]

$\bf sin(\theta)=\cfrac{opposite}{hypotenuse}
=\cfrac{y}{r}
=\cfrac{1}{csc(\theta)}
\\ \quad \\\\
% cosine
cos(\theta)=\cfrac{adjacent}{hypotenuse}
=\cfrac{x}{r}
=\cfrac{1}{sec(\theta)}
\\ \quad \\\\
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}
=\cfrac{y}{x}
=\cfrac{sin(\theta)}{cos(\theta)}$

$\bf cot(\theta)=\cfrac{adjacent}{opposite}
=\cfrac{x}{y}
=\cfrac{cos(\theta)}{sin(\theta)}
\\ \quad \\\\
% cosecant
csc(\theta)=\cfrac{hypotenuse}{opposite}
=\cfrac{r}{y}
=\cfrac{1}{sin(\theta)}
\\ \quad \\\\
% secant
sec(\theta)=\cfrac{hypotenuse}{adjacent}
=\cfrac{r}{x}
=\cfrac{1}{cos(\theta)}\\\\
-------------------------------\\\\
P(x,y)\implies \delta\qquad tan(\delta)=\cfrac{y}{x}$

5 0

3 years ago

I need help with this important question it's for a important grade​

I need help with this important question it's for a important grade