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3 years ago

What is the probability that a customer ordered a hot drink given that he or she ordered a large?

Mathematics

2 answers:

ozzi3 years ago

5 0

Answer:

81 :)

Step-by-step explanation:

valkas [14]3 years ago

4 0

First add the number of total larges ordered 22+5=27 then divide 22/27=.814 to make the answer a percent times by 100. .814x100=81.5% to double check you can multiply .814 by number of larges and should get number of hot larges ordered. .814x27=22

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Piper works at a camera store. He is paid an hourly rate +16% commission on everything he sells. One week, he was paid $515 for

umka21 [38]

His hourly rate is $13.75.

Let x be the hourly rate. Since he works 20 hours that week, the hourly wages are given by 20x. We add to that his commission, which is 16% of the $1500 in sales, or 0.16(1500). This totals to 515:

20x + 0.16(1500) = 515
20x + 240 = 515

Subtract 240 from both sides:
20x + 240 - 240 = 515 - 240
20x = 275

Divide both sides by 20:
20x/20 = 275/20
x = 13.75.

8 0

3 years ago

Y is directly proportional to x when y=30, x=6

rosijanka [135]

Answer:

a) y = 5x

b) y = 60

Step-by-step explanation:

Since, y is directly proportional to x when y=30, x=6

$\therefore \: y \: \alpha \: \: x \\ \therefore \: y = kx ...(1) \\ plug \: y = 30 \: and \: x = 6 \: in \: eq \: (1)\\ 30 = k \times 6 \\ k = \frac{30}{6} \\ k = 5 \\ plug \: k = 5 \: in \: (1) \\ y = 5x....(2) \: (required \: equation) \\ plug \: x = 12 \: in \: eq \: (2) \\ y = 5 \times 12 \\ \huge \red{ \boxed{y = 60}}$

4 0

3 years ago

The following are questions from a self-quiz.According to some study, the height for Northern European adult males is normally d

lara [203]

Answer:

a) 0.064

b) 0.109

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 181 centimeter

Standard Deviation, σ = 7.3 centimeter

We are given that the distribution of height for Northern European adult males is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(person is between 160 and 170 centimeters)

$P(160 \leq x \leq 170) = P(\displaystyle\frac{160 - 181}{7.3} \leq z \leq \displaystyle\frac{170-181}{7.3}) = P(-2.8767 \leq z \leq -1.506)\\\\= P(z \leq -1.506) - P(z < -2.8767)\\= 0.066 -0.002 = 0.064 = 6.4\%$

b) P(person is higher than 190 centimeter)

P(x > 190)

$P( x > 190) = P( z > \displaystyle\frac{190 - 181}{7.3}) = P(z > 1.2328)$

$= 1 - P(z \leq 1.2328)$

Calculation the value from standard normal z table, we have,

$P(x > 190) = 1 - 0.891 = 0.109 = 10.9\%$

7 0

3 years ago

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vladimir2022 [97]

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5 0

3 years ago

One month Sam rented 3 movies and 8 video games for a total of $55 . The next month he rented 5 movies and 2 video games for a t

coldgirl [10]

Answer:

Step-by-step explanation:

You are trying to find the values of two quantities, so you will need to set up a system of two equations in two variables. We'll call M the price of a movie and V the price of a video game.

The first month: 3 movies, 8 video games, $55. Let's translate this into algebra:

3M + 8V = 55

The second month: 5 movies, 2 video games, $18. Translated:

5M + 2V = 18

Solve that system of equations

5 0

3 years ago