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Scrat [10]
2 years ago
12

You paint four walls. Each wall is a rectangle with a length of 20 feet and a height of 10 feet. One gallon of paint covers abou

t 330 square feet. How many gallons of paint do you need in order to cover the walls? Explain.
Mathematics
1 answer:
Sphinxa [80]2 years ago
6 0

Answer:

Step-by-step explanation:

20 x 10= 200 ft

1 gallon is 330 ft

paint 4 walls

200 x 4

800 ft/ 330

You would need 2.434 gallons of paint.

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Maurinko [17]
8 times 2 equals to 16
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PLEASE HELP I WILL BRAINLIEST, MY GPA RELIES ON THIS!! IM BEGGING HERE
MAVERICK [17]

Step-by-step explanation:

it's so much work, here's the first half untill i do the rest

i added the rest, i hope i helped somehow good luck!! :)

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3 years ago
Is the following graph a function
daser333 [38]
You can use the vertical line test to determine if the graph is a function.

A function must: for every x value have only one y value.

Vertical line test: if you draw a bunch of vertical lines each line only touches the graph once.

So a circle would not be a function, or a horizontally facing parabola, etc... Remember, if you draw a vertical line "|" and it touches the graph more than once at any point then it is not a function.

Now take a look at the graph in the question.
In this graph if we do the vertical line test there are no place where a vertical line touches the graph twice so this graph is indeed a function.

This means your answer is C. Yes
7 0
3 years ago
Explain how you know 7(2 - 3n) and (2 - 3n) x 7 are equivalent expressions.​
iogann1982 [59]

Answer:

When you distribute the 7 to each set you get 14-21n and 14-21n

Step-by-step explanation:

5 0
2 years ago
Can you explain how to do 13 please
Zigmanuir [339]
I must confess that I was about to pass this question by, but I was captured by the respectful and dignified way in which you asked for help. 

A careful reading of the problem gives you two equations in two unknowns, which you can then solve as simultaneous equations.  Here's how it looks:

Call 'C' the price of the senior <u>C</u>itizen ticket.
Call 'S' the price of the <u>S</u>tudent ticket.

On the first night . . .    10 C  +  12 S  =  208

On the second night . . .  8C  +  3 S  =  74

Those are your two simultaneous equations. Now the idea is to multiply or divide each side of one equation in such a way that when you add or subtract it from the other equation, one of the variables will become a zero quantity ...  you'll be left with an equation in one variable, which you can easily solve. THEN, knowing the value of one variable, you can put it back into one of the original equations,and find the value of the other variable.

This all sounds more complicated than it is.   Here's how it goes:
We have . . .

10 C  +  12 S  =  208  and
8C  +  3 S  =  74

I'm going to multiply each side of the second equation by  4, and then write it under the first one:

10 C  +  12 S  =  208
32 C  +  12 S  =  296

Now, subtract the lower equation from the upper one, and you get . . .

- 22 C  +  0  =   - 88

Divide each side of this one by  -22  and you have    <em>C = $4.00</em> .

THAT's what you need, to blow the whole problem wide open.  Knowing
the value of 'C', let's substitute it into the equation for the first night:

10 C  +  12 S  =  208

10(4)  +  12 S  =  208

40  +  12 S  =  208

Subtract  40  from each side :    12 S  =  168

Divide each side by  12 :    <em>S  =</em><em>  $ 14.00 </em>.

Finally, as we look over our results, and see that Students have to pay  $14  to see the show but Seniors can get in for only  $4 , we reflect on this ... or at least I do ... and realize that getting old is not necessarily all bad.
3 0
3 years ago
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