Rotation and translation are rigid transformations, they don't change figure sizes. Dilation change figure sizes increasing or decreasing them by scale factor.

First, find AB and A'B' by the formula:

$AB=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}= \sqrt{(8-0)^2+(8-(-7))^2}=\sqrt{8^2+15^2}=\sqrt{64+225}=\sqrt{289}=17,\\ \\A'B'=\sqrt{(x_{B'}-x_{A'})^2+(y_{B'}-y_{A'})^2}= \sqrt{(2-6)^2+(1.5-(-6))^2}=\sqrt{4^2+7.5^2}=\sqrt{16+56.25}=\sqrt{72.25}=8.5.$

As you can see AB=2A'B'. This means that the segment AB was decreased twice to form segment A'B'. Then the scale factor is 1/2.

8 0

3 years ago

I will give brainliest

Alja [10]

1. The answer is 16^2, so B.

16 x 16 = 256

2. The answer is 17, so B.

Some of the factor of 68 are: 1, 2, 4, 17, 34 and 68.

3. The answer is 15, so B.

Only 15 is composite since it contains more than a factor, which are 3 and 5. The rest of the numbers are prime since they only contain a factor.

4. The answer is 2^2^3^7, so B.

The factor tree:

2 x 42

2 x 2 x 21

2 x 2 x 3 x 7

Hope this helps! :)

3 0

3 years ago