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zhannawk [14.2K]
3 years ago
7

A movie theater kept attendance on Fridays and Saturdays throughout the year.

Mathematics
2 answers:
AnnZ [28]3 years ago
8 0

Answer: The answer is D.

Step-by-step explanation: I found this because if you look at the plotted median on Friday it is greater than that of Saturday’s and if you look at the interquartile range plotted then you can see that it looks the same.

Hope this helps.

irina [24]3 years ago
8 0
For this question :The answer is D
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A circular garden has a diiameter of 6 yards what is the area of the garden use 3.14 for Tt
Rom4ik [11]

Given the diameter of the circular garden, the area of the garden is 28.36 yd².

<h3>What is the area of the garden?</h3>

The area of a circle is expressed as; A = πr²

Given that;

  • Diameter d = 6yd
  • Radius r = d/2 = 6yd/2 = 3yd
  • Area A = ?

A = πr²

A = 3.14 × (3yd)²

A = 3.14 × 9yd²

A = 28.36 yd²

Given the diameter of the circular garden, the area of the garden is 28.36 yd².

Learn more about circles here: brainly.com/question/11952845

#SPJ1

6 0
2 years ago
Putting numbers from scientific notation to standard notation
Alla [95]
There is this really good video that explains it all:
https://www.youtube.com/watch?v=AWof6knvQwE
4 0
3 years ago
Hellpppppppppppppppppppppppppppppppppppppppp
natulia [17]

Answer:

._.     -_-     -.-    .-.   --__--

Step-by-step explanation:

8 0
3 years ago
Use vector notation to describe the points that lie in the given configuration. (Let s and t be elements of the Reals.)
Blababa [14]

Answer: I(s,t) = {(6s, 5s+6t, 5t)| sER, tER }

Step-by-step explanation:

Given the data in the question;

A vector is in the span of V1 and V2 only if it is a linear combination.

of V1 and V2.

so 'V' is in the span if;

V = SV1 + tV2 [ S and t are real numbers ]

V =    [ 6si + 5sj ] + [ 6tj + 5tz]

V = 6s, 5s+6t, 5t

so

I(s,t) = {(6s, 5s+6t, 5t)| sER, tER }

5 0
3 years ago
Please answer the full question and make sure to specify which triangle is equal to triangle AMN and by which of the following r
Brums [2.3K]

Answer:

See Below.

Step-by-step explanation:

<u>Statements:</u>                                      <u>Reasons:</u>

<u />1)\text{ } \overline{MN} \parallel \overline{AO}\text{ and } \overline{AM} \parallel \overline{ON}              Given

2)\text{ } AMNO\text{ is a parallelogram}             Definition of a parallelogram

3)\text{ } \overline{AM}\cong\overline{ NO}                                     Opposite sides of a parallelogram are ≅.

4)\text{ } \overline{MN }\cong\overline{ OA}                                     Opposites sides of a parallelogram are ≅.

5)\text{ } \overline{AN}\cong\overline{AN}                                       Reflexive Property.

6)\text{ } \Delta AMN\cong \Delta NOA                          SSS Congruence.

Notes: AAA and SAA are not theorems of congruence.

4 0
3 years ago
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