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3 years ago

Factor completely 2x^3+6x^2+10x+30

Mathematics

2 answers:

beks73 [17]3 years ago

7 0

Answer:

2(x+3) (x^2 + 5)

Step-by-step explanation:

Digiron [165]3 years ago

5 0

2x^3 + 6x^2 + 10x + 30

Factor:

2x^3 + 6x^2 + 10x + 30

= 2(x + 3)(x^2 + 5)

So your answer is 2(x + 3)(x^2 + 5)

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Find the roots of the quadratic equation x^2 – 8x = 9 by completing the square. Show your work.

loris [4]

X² - 8x = 9
x² - 8x - 9 = 0
x² + x - 9x - 9 = 0
x(x + 1) -9(x + 1) = 0
(x+1)(x-9) = 0
x = -1 or 9

In short, Your Answers would be -1 & 9

Hope this helps!

3 0

3 years ago

If an equation has two roots -4 and 7, what could be the<br> quadratic equation?

aleksklad [387]

Answer:

f(x) = x^2 - 3x - 28

Step-by-step explanation:

The root -4 corresponds to the factor (x + 4); the root 7 corresponds to (x - 7). The equation is thus f(x) = (x + 4)(x - 7) = x^2 - 3x - 28, or

f(x) = x^2 - 3x - 28

8 0

3 years ago

Nathan has $40 in a savings account. The interest rate is 5% per year and is not

fgiga [73]

Money with Nathan in his savings account = $40

Rate of interest per annum = 5%

We know that :

$\color{hotpink}\tt \: simple \: interest \color{plum}= \frac{principal \times rate \times time}{100}$

In this case :

Principal = $40

Rate = 5%

Time = 1 year

Simple interest he will earn in 1 year :

$=\tt \frac{40 \times 5 \times 1}{100}$

$= \tt \frac{200}{100}$

$\color{plum} =\tt\$ \: 2$

Amount = Principal + Interest

Amount Nathan has to pay at the end of one year :

$= \tt40 + 2$

$\color{plum} =\tt \$42$

Thus, at the end of 1 year Nathan has to pay $42.

Therefore, simple interest Nathan will earn in 1 year = $2

6 0

3 years ago

Find the sum or difference of 1/12 + 7/9

Arturiano [62]

Find a common denominator between 12 and 9
it would be 36
9*4=36
12*3=36
1*3=3
7*4=28
3/36 + 28/36 = 31/36

4 0

4 years ago

3 3/8 T = lb what does this equal

AnnyKZ [126]

Answer:

3375lbs

Step-by-step explanation:

3 0

3 years ago