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lana [24]
2 years ago
9

Factor completely 2x^3+6x^2+10x+30

Mathematics
2 answers:
beks73 [17]2 years ago
7 0

Answer:

2(x+3) (x^2 + 5)

Step-by-step explanation:

Digiron [165]2 years ago
5 0

2x^3 + 6x^2 + 10x + 30

Factor:

2x^3 + 6x^2 + 10x + 30

= 2(x + 3)(x^2 + 5)

So your answer is 2(x + 3)(x^2 + 5)

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Lacey decides to take her five year old son to the history museum. The price for the child's ticket is 2.75 dollars less than th
Andrei [34K]
If the price for the adult ticket is $2.75 more than the child ticket, the adult ticket would be x + $2.75
3 0
3 years ago
WILL MARK BRAINLIEST ANSWER!!!
STatiana [176]

Answer:

7. D:61

8. A:57

9. A: 47

Step-by-step explanation:

Quesiton 7:

To find perimeter we add all the sides together.

x+2x+2x+5=145

Combine all the x's.

5x+5=145

To isolate the constants, subtract 5 from both sides.

5x=140

Now divide both sides by 5 to isolate the x.

x=28

The questions asks for the length of AC, so to find that we need to insert our new x.

AC= 2(28)+5

56+5=61

6 0
3 years ago
Factor f(x)=x4+x3-20x2.
Leya [2.2K]

Hello from MrBillDoesMath!

Answer:

-5, 0 (multiplicity 2), +4


Discussion:

Let f(x) = x^4 + x ^3 - 20 x^2

Factor x^2 from each term:

f(x) = x^2 ( x^2 + x - 20) = x^2 ( x +5) (x-4)

f = 0 when x = 0 (multiplicity 2) and x = -5 or x = 4



Regards,  

MrB


7 0
2 years ago
Solve the equation for x. 3 In(x) + 2 In (4)= In(128)
Scilla [17]

Answer:

x=2

Step-by-step explanation:

3 ln(x) + 2 ln (4)= ln(128)

a ln (b) = ln b^a

In(x^3) +  In (4^2)= In(128)

In(x^3) +  In (16)= In(128)

ln a + ln b = ln (ab)

In(16x^3) = In(128)

raise each side to the power of e

e^ In(16x^3) = e ^In(128)

e^ ln  cancels out

(16x^3) = (128)

divide by 16

(16x^3)/16 = (128)/16

x^3 = 8

take the cube root on each side

(x^3)^1/3 = 8^ 1/3

x =2



8 0
3 years ago
Write an equation in standard form for a line that passes through (4,1) & (5,7)
tatuchka [14]
Y = mx + b

First equation 1 = m(4) + b, bring everything to one side m(4) + b - 1 = 0
Second equation 7 = m(5) + b, bring everything to one side m(5) + b - 7 = 0

Set them equal to each other, 

m(4) + b - 1 = m(5) + b - 7

If you bring the b over to the left hand side it becomes

m(4) + b - b - 1 = m(5) - 7

m(4) - 1 = m(5) - 7

Solve for m

6 = m

Plug m = 6 into either equation from the beginning,

m(4) + b - 1 = 0

6(4) + b - 1 = 0

24 + b - 1 = 0

b = -23

Knowing m and b we can now make an equation

y = mx + b

y = 6x -23 Final answer



3 0
2 years ago
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