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liraira [26]
3 years ago
10

Ellie has a 352-ounce bag of dog food. Her dog eats 24 ounces each day. How many full days will Ellie feed her dog before she ne

eds another bag of dog food?
Mathematics
1 answer:
krek1111 [17]3 years ago
3 0

Answer: 14 days

Step-by-step explanation:

352/24= 14.66666667

So it can feed her dog for 14 full days

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X+y+z=1<br> X-2y+3z=2<br> X+z-5=0
serious [3.7K]

x+y+z=1

x=1/(y+z)

1/(y+z)-2y+3z=2  

1-2y²-2yz+3yz+3z²=2(y+z)

(1-2y²+yz+3z²)/2=y+z

z=(1-2y²+yz+3z²)/2 -y/1

z=(1-2y²+yz+3z²-2y)/2

8 0
3 years ago
Please help! and show some sort of work so i know its correct! thanks&lt;3
pychu [463]

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Answer:

  C.  parallelogram, then rectangle

Step-by-step explanation:

The attached image shows how the shape evolves as the number of segments of the circle increases. The smaller the central angle, the closer the shape becomes to a rectangle.

3 0
3 years ago
1/3 plus what number gives you 5/4
stira [4]

<u><em>The answer is 11/12.</em></u>

<u><em>I got the answer by subtracting 5/4-1/3 and the answer would be the answer to the problem.</em></u>

<u><em>Hope this helps!</em></u>

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8 0
3 years ago
Please help on these 2 questions.
Law Incorporation [45]

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Step-by-step explanation:

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6 0
3 years ago
Read 2 more answers
Hailey sold 20 tickets to the school play for a total of 225$.Early bird tickets were 10$ and regular priced tickets were 15$.Wr
dlinn [17]

Answer:

The system of equation are \left \{ x+y=20} \atop {10x+15y=225}} \right.

The number of early bird tickets are <u>15</u> and of regular tickets are <u>5</u>.

Step-by-step explanation:

Given,

Total number of tickets = 20

Total amount = $225

Solution,

Let the number of early bird tickets be 'x'.

And also let the number of regular tickets be 'y'.

Now total number of tickets is the sum of number of early bird tickets and number of regular tickets.

So framing in equation form, we get;

Total number of tickets = number of early bird tickets + number of regular tickets

x+y=20\ \ \ \ equation\ 1

Again, Total amount is the sum of number of early bird tickets multiplied with price of each ticket and number of regular tickets multiplied with price of each ticket.

So framing in equation form, we get;

10x+15y=225\ \ \ \ \ equation\ 2

Hence the system of equation are \left \{ x+y=20} \atop {10x+15y=225}} \right.

Now we solve the equation by multiplying equation 1 by 10, and get;

10(x+y)=20\times10\\\\10x+10y=200\ \ \ \ equation\ 3

Now subtracting equation 3 from equation 2, we get;

(10x+15y)-(10x+10y)=225-200\\\\10x+15y-10x-10y=25\\\\5y=25\\\\y=\frac{25}{5}=5

On substituting the value of 'y' in equation 1, we get;

x+y=20\\\\x+5=20\\\\x=20-5=15

Hence The number of early bird tickets are <u>15</u> and of regular tickets are <u>5</u>.

3 0
3 years ago
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