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2 years ago

PLEASE HELP I WILL GIVE BRANLIEST IF YOUR ANSWER IS CORRECT!

Mathematics

2 answers:

Tamiku [17]2 years ago

5 0

1:4 2:8 3:12 4:16 because every one is adding 4 hope this helps. ;)

Vilka [71]2 years ago

3 0

Answer:

1:4

2:8

3:12

4:16

Step-by-step explanation:

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Solve for y:y= [-7-6]<br><br>answers:<br> (a)-13 (b)13 (c)1 (d) -1 (e) none of these

Natali [406]

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Hi my lil bunny!

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$y= [-7-6]$

$y = -13$

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Have a great day/night!

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8 0

3 years ago

Which numbers below belong to the solution set of the equation 16x=224

Taya2010 [7]

x would equal 14 hope this helps

5 0

2 years ago

Do bonds reduce the overall risk of an investment portfolio? Let x be a random variable representing annual percent return for t

rjkz [21]

Answer:

COV (all stocks) = 0.55

COV (stocks and bonds) = 0.82

Step-by-step explanation:

Coefficient of Variation is used to measure variability.

It is defined as the ration of standard deviation and the mean.

It can be used to compare variability of two population or two samples.

Formula:

$\text{Coefficient of Variation} = \displaystyle\frac{\text{Standard Deviation}}{\text{Mean}}$

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

x: 14, 0, 39, 25, 32, 27, 28, 14, 14, 15

$Mean = \frac{208}{10} = 20.8$

$Standard~Deviation = \sqrt{\frac{1169.6}{9} } = 11.39$

$Coefficient~of~Variation = \frac{11.39}{20.8} = 0.55$

y = 6, 2, 29, 17, 26, 17, 17, 2, 3, 5

$Mean = \frac{124}{10} = 12.4$

$Standard~Deviation = \sqrt{\frac{924.4}{9} } = 10.13$

$Coefficient~of~Variation = \frac{10.13}{12.4} = 0.82%$

Since coefficient of variation of x is less compared to y, thus it could be said bonds does not reduce overall risk of an investment portfolio.

6 0

2 years ago

Factor the polynomial function over the complex numbers. f(x)=x^3-2x^2+3x-6

Airida [17]

$f(x)=x^3-2x^2+3x-6=x^2(x-2)+3(x-2)=(x-2)(x^2+3)\\\\i=\sqrt{-1}\to i^2=-1\\\\x^2+3=x^2-(-3)=x^2-3i^2=x^2-(\sqrt3)^2i^2)=x^2-(i\sqrt3)^2\\\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\\boxed{f(x)=(x-2)(x-i\sqrt3)(x+i\sqrt3)}$

6 0

3 years ago

Help please

yawa3891 [41]

Answer:

C. 4.6

Step-by-step explanation:

If you subtract 3.0 from 1.4 you get 1.6, which is the can be added to 3.0 to find the missing value.

8 0

2 years ago