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mestny [16]
3 years ago
10

Rectangle ABCD has vertices at A(-1,1), B(2,1), C(2,-5), and D(-1,-5). What is the perimeter of rectangle

Mathematics
1 answer:
Drupady [299]3 years ago
8 0

Answer:

The perimeter of the rectangle is 18 units.

Step-by-step explanation:

The image included below presents the location of the points on the Cartesian plane. From Geometry we get that the perimeter (p), dimensionless, of the rectangle is the sum of its four sides. That is to say:

p = AB+BC+CD+DA (1)

Where AB, BC, CD and DA are the sides of the rectangle, dimensionless.

Each side value is found by means of the Pythagorean Theorem:

AB = \sqrt{[2-(-1)]^{2}+(1-1)^{2}}

AB = 3

BC = \sqrt{(2-2)^{2}+[(-5)-1]^{2}}

BC = 6

CD = \sqrt{(-1-2)^{2}+(5-5)^{2}}

CD = 3

DA = \sqrt{(-1-1)^{2}+[1-(-5)]^{2}}

DA = 6

And the perimeter of the rectangle is:

p = 3+6+3+6

p = 18

The perimeter of the rectangle is 18 units.

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<h3><em>Hey there today we will solve your problem,</em></h3>

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<h3>Definitions</h3>
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