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Strike441 [17]
3 years ago
8

What is the equation, In factored form, of the quadratic function shown in the graph?

Mathematics
1 answer:
OlgaM077 [116]3 years ago
8 0

Given:

The graph of a quadratic function.

To find:

The equation of the quadratic function in factored form.

Solution:

From the given graph it is clear that the graph of the function intersect the x-axis at point (-3,0) and (2,0).

Since -3 and 2 are the zeros of the function, therefore (x+3) and (x-2) are the factors of the required quadratic function.

Now, the function can be written as:

f(x)=a(x+3)(x-2)             ...(i)

The graph of the function intersect the y-axis at (0,-6). Substituting x=0,f(x)=-6 in (i), we get

-6=a(0+3)(0-2)

-6=a(3)(-2)

-6=-6a

\dfrac{-6}{-6}=a

1=a

Substituting a=1 in (i), we get

f(x)=1(x+3)(x-2)

Therefore, the required function is f(x)=1(x+3)(x-2).

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Find the product. y5 · y3
dem82 [27]

Answer:

Step-by-step explanation:

y^5*y^3=y^{5+3}=y^8

5 0
3 years ago
What is the interval when written in the form of (lower limit, upper limit)(lower limit, upper limit) ?
Stels [109]
The interval <span>when written in the form of lower limit and the upper limit would be 95.8 - 98.2. This can be calculated by subtracting 95 with 1.2 and by adding 95 with 1.2. Hope this answers the question. Have a nice day. Feel free to ask more question.</span>
8 0
3 years ago
The sum of two terms of gp is 6 and that of first four terms is 15/2.Find the sum of first six terms.​
Gnoma [55]

Given:

The sum of two terms of GP is 6 and that of first four terms is \dfrac{15}{2}.

To find:

The sum of first six terms.​

Solution:

We have,

S_2=6

S_4=\dfrac{15}{2}

Sum of first n terms of a GP is

S_n=\dfrac{a(1-r^n)}{1-r}              ...(i)

Putting n=2, we get

S_2=\dfrac{a(1-r^2)}{1-r}

6=\dfrac{a(1-r)(1+r)}{1-r}

6=a(1+r)                    ...(ii)

Putting n=4, we get

S_4=\dfrac{a(1-r^4)}{1-r}

\dfrac{15}{2}=\dfrac{a(1-r^2)(1+r^2)}{1-r}

\dfrac{15}{2}=\dfrac{a(1+r)(1-r)(1+r^2)}{1-r}

\dfrac{15}{2}=6(1+r^2)            (Using (ii))

Divide both sides by 6.

\dfrac{15}{12}=(1+r^2)

\dfrac{5}{4}-1=r^2

\dfrac{5-4}{4}=r^2

\dfrac{1}{4}=r^2

Taking square root on both sides, we get

\pm \sqrt{\dfrac{1}{4}}=r

\pm \dfrac{1}{2}=r

\pm 0.5=r

Case 1: If r is positive, then using (ii) we get

6=a(1+0.5)  

6=a(1.5)  

\dfrac{6}{1.5}=a  

4=a

The sum of first 6 terms is

S_6=\dfrac{4(1-(0.5)^6)}{(1-0.5)}

S_6=\dfrac{4(1-0.015625)}{0.5}

S_6=8(0.984375)

S_6=7.875

Case 2: If r is negative, then using (ii) we get

6=a(1-0.5)  

6=a(0.5)  

\dfrac{6}{0.5}=a  

12=a  

The sum of first 6 terms is

S_6=\dfrac{12(1-(-0.5)^6)}{(1+0.5)}

S_6=\dfrac{12(1-0.015625)}{1.5}

S_6=8(0.984375)

S_6=7.875

Therefore, the sum of the first six terms is 7.875.

5 0
3 years ago
Which of the following lines are shown in the drawing?
scZoUnD [109]

Answer:

  • A, B, D

Step-by-step explanation:

According to the drawing we can see the lines

  • A) LI, yes
  • B) GJ, yes
  • C) CJ, no
  • D) BE, yes
  • E) FA, no
8 0
2 years ago
A professional soccer player kicked a ball across the field. The ball’s height, in meters, is modeled by the function graphed be
pantera1 [17]

Answer:

Hey there!

You can think of the rate of change as the slope of a quadratic function- here we see that it is 9/-3, or - 3.

Let  me know if this helps :)

6 0
3 years ago
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