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juin [17]
2 years ago
5

Solve for x: 3x = -9

Mathematics
2 answers:
inessss [21]2 years ago
7 0

Answer:

x = -3

Step-by-step explanation:

thats your answer

KIM [24]2 years ago
3 0
Answer x = -3

Divide both side by 3
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Solve for X<br>4x + 8 = 2x + 2​
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Answer:

x = -3

Step-by-step explanation:

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Help me plz !!!<br> What property does the equation show?
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2 years ago
2. If f(x) = 2X^2 + 3X Find f(-5)
IgorLugansk [536]

Answer:

35

Step-by-step explanation:

2(-5)^2+3(-5)

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4 0
2 years ago
Find the midpoint of the line seg<br> (-4, -2) and (3, 3)
Serggg [28]

Answer:

Step-by-step explanation:

(-4 + 3)/2= -1/2

(-2 + 3)/2= 1/2

(-1/2, 1/2) the midpoint

6 0
2 years ago
A magazine provided results from a poll of 500500 adults who were asked to identify their favorite pie. Among the 500500 ​respon
Komok [63]

Answer:

99% confidence interval is wider as compared to the 80% confidence interval.

Step-by-step explanation:

We are given that a magazine provided results from a poll of 500 adults who were asked to identify their favorite pie.

Among the 500 respondents, 14​% chose chocolate​ pie, and the margin of error was given as plus or minus ±3 percentage points. 

The pivotal quantity for the confidence interval for the population proportion is given by;

                            P.Q.  =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of adults who chose chocolate​ pie = 14%

            n = sample of adults = 500

            p = true proportion

Now, the 99% confidence interval for p =  \hat p \pm Z_(_\frac{\alpha}{2}_)  \times \sqrt{\frac{\hat p(1-\hat p)}{n} }

Here, \alpha = 1% so  (\frac{\alpha}{2}) = 0.5%. So, the critical value of z at 0.5% significance level is 2.5758.

Also, Margin of error = Z_(_\frac{\alpha}{2}_)  \times \sqrt{\frac{\hat p(1-\hat p)}{n} }  = 0.03 for 99% interval.

<u>So, 99% confidence interval for p</u>  =  0.14 \pm2.5758  \times \sqrt{\frac{0.14(1-0.14)}{500} }

                                                        = [0.14 - 0.03 , 0.14 + 0.03]

                                                        = [0.11 , 0.17]

Similarly, <u>80% confidence interval for p</u>  =  0.14 \pm 1.2816  \times \sqrt{\frac{0.14(1-0.14)}{500} }

Here, \alpha = 20% so  (\frac{\alpha}{2}) = 10%. So, the critical value of z at 10% significance level is 1.2816.

Also, Margin of error = Z_(_\frac{\alpha}{2}_)  \times \sqrt{\frac{\hat p(1-\hat p)}{n} }  = 0.02 for 80% interval.

So, <u>80% confidence interval for p</u>  =  [0.14 - 0.02 , 0.14 + 0.02]

                                                           =  [0.12 , 0.16]

Now, as we can clearly see that 99% confidence interval is wider as compared to 80% confidence interval. This is because more the confidence level wider is the confidence interval and we are more confident about true population parameter.

5 0
3 years ago
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