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3 years ago

What is the least common factor of 8 ,9,and 10?

Mathematics

2 answers:

Ksivusya [100]3 years ago

8 0

360
if you are looking for more answers of LCF there are tons of calculators you can use online and videos that will explain it to you
Good Luck

PilotLPTM [1.2K]3 years ago

3 0

I hope this helps you

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Put Them in The box They Go in

pav-90 [236]

Answer:

$\frac{1}{3} \times r - 4 \\ 3 \times r - 4 \\ \frac{1}{3} \times r + 4 \\ 3(r + 4)$

5 0

3 years ago

Susanna has played the piano for s years. Patrick has played the piano for 4 more than twice the number of years that Susanna ha

scoray [572]

S=Years Susanna has played the piano
p=Years Patrick has played the piano

The expression for this question would be s(2)+4=p

Hope this helps! :)

6 0

3 years ago

Read 2 more answers

Expalin what the vertical line test is and it used ?

katovenus [111]

Answer:

You use the vertical line test to see if a function is relation is a function

Step-by-step explanation:

A function is a relation with only one output for every input. That means that if the x value and two y values, it is not a function.

5 0

3 years ago

Read 2 more answers

Consider this expression.

schepotkina [342]

Answer:

$9m^2 + 17m- 9$

Step-by-step explanation:

Given

$7m^2 + (2m - 1)(m + 9)$

Required:

Simplify

We start by opening the bracket

$7m^2 + (2m(m + 9) - 1(m + 9))$

$7m^2 + 2m^2 + 18m - m - 9$

Collect Like Terms

$9m^2 + 17m- 9$

Hence, the equivalent expression is $9m^2 + 17m- 9$

5 0

3 years ago

Dinosaur fossils are often dated by using an element other than carbon, like potassium-40, that has a longer half life (in this

Firlakuza [10]

The amount of substance left of a radioactive element of half life, $t_{\frac{1}{2}}$ after a time, t, is given by:

$N(t)=N_0\left( \frac{1}{2} \right)^ \frac{t}{t_{ \frac{1}{2} }}$

Given that <span>potassium-40 has a half life of approximately 1.25 billion years.

The number of years it will take for 0.1% of potassium-40 to remain is obtained as follows:

$0.1=100\left( \frac{1}{2} \right)^ \frac{t}{1.25}} \\ \\ \Rightarrow\left( \frac{1}{2} \right)^ \frac{t}{1.25}}=0.001 \\ \\ \Rightarrow\frac{t}{1.25}\ln\left( \frac{1}{2} \right)=\ln(0.001) \\ \\ \Rightarrow \frac{t}{1.25}= \frac{\ln(0.001)}{\ln\left( \frac{1}{2} \right)} =9.966 \\ \\ t=9.966(1.25)=12.5$

Therefore, </span><span>the maximum age of a fossil that we could date using 40k is 12.5 billion years.</span>

3 0

3 years ago