Answer:
Simply here we use system of 2 equations.
Step-by-step explanation:
Let x be the cost of one small shirt and let y be that of one large shirt.
(4x +14y =210) (-3)
12x +11y =110
-12x - 42y= -630 note:cross 12x and - 12x
12x +11y =110
__________
-42y +11y = - 630 +110
-31y = -520
Y=520/31
Replace y in second equation:
12x +11y =110
12x +11(520/31) =110
12x +5720 =110
12x =110 - 5720/31
X= - 385/62
So one small shirt costs - 385/62 $
And a large one costs 520/31 $
Though I think there's something wrong in this problem since i verified my answer using calculator the same prices are obtained and as u see the cost of a small shirt is negative which is unbelievable.. So plz make sure from anyone else. I tried my best to help.
Answer:
10. Let m<Y = y.
Then,
m<Y + m<X +m<Z = 180 [ Sum of angles of triangle is 180 degrees]
or, y + (6x-23) + (4x + 9) = 180
or, y + 10x -14 = 180
or, y = 194 - 10x
or, m<Y = 194 - 10x
12. Solution,
a. m<1 = 60 degrees [Each angles of equilateral triangle is equal to 60 degrees]
b. In triangle WYZ,
m<Z + m<ZWY + m<ZYW =180 [Sum of angles of triangle is 180]
or, 138 + m<ZWY +m<ZWY =180 [Base angles of isosceles triangle are equal, i.e. m<ZYW = m <ZWY]
or, 2 (m<ZWY) = 180 -138 = 42
or, m<ZWY = 21 = m<ZYW
or, m<3 = 21 = m<5
c. Solution,
m<XWY = m<2 + m<3 [Addition axiom]
or, 60 = m<2 + 21 [Each angle of equilateral triangle is 60]
or, m<2 = 39
d. Solution,
m<4 + m<5 =60 [<XYW = 60 ]
or, m<4 + 21 = 60
or, m<4 = 39
The ratio of wilma/teddy is 6/5 , if teddy has X then she has 21+X so you can solve X in this equation 6/5 = (21+x)/x
Let x be Jake's number of sold tickets. Sara's number is half as Jake's, so x/2 while, Cole's number is twice as Jake's, 2x. The equation that represents the problem is just the summation of their sold tickets. Therefore, 538= x+ x/2 + 2x, further simplifying the equation, it becomes, 538= 7/2 x. Solving for Jake's number of tickets, Sara and Cole's number of tickets can be determined.
