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snow_lady [41]
3 years ago
12

Philip wants to enclose his garden using 30 meters of fence. What is the largest interger value area, in square meteres, that he

can enclose? What are the dimensions of the rectangular enclosure for his garden?
​
Mathematics
1 answer:
Nostrana [21]3 years ago
6 0

Answer:

36

Step-by-step explanation:

divide then subtract

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PSYCHO15rus [73]
I think its A but im not absolutely sure

4 0
3 years ago
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Paid for $22 for for movie tickets how many would they have pay for for 16 tickets
bija089 [108]

Answer:

$352

Step-by-step explanation:

One ticket costs $22, so 16 tickets would be 22 times 16.

Final Answer: $352

5 0
3 years ago
Two numbers have theses properties . both numbers are greater than 6 . their hcf = 6 . their lcm = 60. what are the two numbers
aleksandrvk [35]
Let the numbers be x and y.
x*y=HCF*LCM=6*60=360
thus
y=360/x
next we find the list of combinations of x and y and test if they satisfy the conditions above:
(6,60),(12,30),(18,20),(24,15)
out of the above, only (6,60) and (12,30) satisfy both conditions. Thus our answer is:
(6,60) or (12,30)
6 0
3 years ago
suppose six of these people are men, and the other six are women. in how many ways can they join hands for a circle dance, assum
Drupady [299]

Twelve people join hands for a circle dance.In how many ways can they do this? Suppose six of these people are men, and the other six are women. In how many ways can they join hands for a circle dance, assuming they alternate in gender around the circle

Answer:

86400 ways

Step-by-step explanation:

Since the circle can be rotated, the number of ways to arrange a distinct number of n objects in a circle will be (n−1)!.

Now, if we rotate the circle with the six women, we will see that there are 5! ways with which they can be placed in the circle.

After picking the places for the women, we will now fill each gap between two women with a man.

We have 6 men. Thus, number of ways to arrange the men is 6!

Thus,number of ways they can join hands for a circle dance, assuming they alternate in gender around the circle = 5! × 6! = 86400 ways

8 0
3 years ago
The equation of line A is y = 7x + 12. Line B is perpendicular to line A and passes through the point . What would be the soluti
max2010maxim [7]
Since B is perpendicular to A. We can say that the gradient of B will be -1/7 (product of the gradients of 2 perpendicular lines has to be -1).
Now we know that the equation for B is y=-(1/7)x + c with c being the y intercept.
Since the point isnt specified in the question, we could leave the equation like this.
But if there is a given point that B passes through, just plug in the x and y values into their respective places and solve to find c. That should give you the equation for b.
Now, to find the solution of x, we have 2 equations:
1) y=7x+12
2)y=-(1/7)x+c

In this simultaneous equation we see that y is equal to both the expressions. So,
7x+12=-(1/7)x+c

Now, since the value of c is not found, we cannot actually find the value of x, but if we would find c, we could also find x since it would only be a matter of rearranging the equation.
And there you go, that is your solution :)
3 0
3 years ago
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