105 different outfits can wear on an individual day
<em><u>Solution:</u></em>
I have 7 button down shirts, 5 pairs of pants and 3 pairs of shoes that I can wear to work
To find: Number of different outfits can I wear on an individual day
First he has to decide on a pair of pants and he has 5 different choices
For each of those choices he has a choice of 7 different button down shirts, so that gives him 5 x 7 = 35 different pant/shirt combinations
For each of those 35 different pant/shirt combinations, he has 3 pairs of shoes he could select, so altogether he has 35 x 3 = 105 different outfits
In short we can say,
different outfits = 7 x 5 x 3 = 105
So there 105 different outfits can wear on an individual day
Answer:
8.6
Step-by-step explanation:
This uses the Pythagorean Theorem
a^2 + b^2 = c^2
a = 5
b = 7
c = ?
5^2 + 7^2 = c^2
25 + 49 = c^2
74 = c^2
sqrt(c^2) = sqrt(74)
c = 8.60 which when rounded = 8.6
To do this add all the numbers up then divide it by the amount of numbers there are
Answer:
If x is my daughter's age now, my age now is 4x. So now my daughter is 10 years old, and I'm 40 years old, and in 20 years she'll be 30 and I'll be 60, twice as hers.
Step-by-step explanation:
Answer:
a- 10x^2 - 4x + 12
b- no, the first equation is −1/4⋅(5x^2+6x−24) and the second is -1/4⋅(10x^2+7x-24)
Step-by-step explanation:
m6th w6y
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