Well first you divide 116 by 29, and get 4. Then you multiply that 4 by the 3 and you get 12. So 3/29 = 12/116.
Answer:The other values of x are -1 and 2
Step-by-step explanation:
Answer:
Step-by-step explanation:
The formula for projectile motion in this case where we're dealing the "American" measure of gravity in feet per second squared, is
where s(t) is the height of the object after a certain amount of time has gone by, v₀ is the initial vertical velocity (our unknown in this case), and h₀ is the initial height.
For us, the initial height is 0 because the ball started off on the ground. What we are being asked is what is v₀, when after 2 seconds have gone by and the ball is 94 feet in the air. 94 feet in the air is the position of the ball, s(t) after t seconds go by. What we are being asked to find then, is v₀ when s(2) = 94
which simplifies to
94 = -64 + 2v₀ and
158 = 2v₀ so
v₀ = 79 feet per second
To figure ut the roots use the quadratic formula
x = [-b +- sqrt(b^2-4ac)]/2a
x = [-k +- sqrt(k^2-4(1)(5)]/2(1)
x = [-k + sqrt(k^2 - 20)]/2 or [-k - sqrt(k^2 - 20)]/2
So the question says these roots differ by sqrt 61, so let's subtract each
[-k + sqrt(k^2 - 20)]/2 - [-k - sqrt(k^2 - 20)]/2
well the k's cancel in the beginning and we are left with 2sqrt(k^2 - 20)/2, and the 2 on top and bottom reduce to
sqrt(k^2 - 20), so this equals sqrt 61
Set equal and solve
sqrt(k^2 - 20) = sqrt(61)
k^2 - 20 = 61
k^2 = 81, so k = +9 or -9
The greatest value therefore is k = +9.
Answer:
area = 148.72 ft^2
Step-by-step explanation:
height =sin 55 x 16.5
height =0.8192 x 16.5
height = 13.52
area=0.5 x base x height
area = 0.5 x 22 x 13.52
area = 148.72 ft^2