Answer:
fe4trhegweggwerg4twerewerth54h4hyrht5th53h
Step-by-step explanation:
216 =6^3
1,296 = 6^4
7,776 = 6^5
x = 6^f(x)
log x = log 6^f(x) = f(x)log 6
f(x) = log x / log 6 =
Answer:
x = 4.4
Step-by-step explanation:
I'm going to assume you want to solve for x so here we go.
You need to work backwards for this equation, and whatever you do to the LHS, you do to the RHS.
First, you need to remove the minus 3, which means that on both sides, you add 3. Adding three on the LHS makes the -3 disappear, and adding 3 on the RHS makes the 19 go to a 22.
Your equation is now 5x=22.
Since 5x means 5 × x, to get rid of it, you need to divide 5x by 5. Doing it to the LHS will make the five disappear, and doing it to the RHS will make it go to 22 ÷ 5 which equals 4.4
Therefore, x = 4.4
Answer:
B
Step-by-step explanation:
<u>This is a right triangle as shown by the right angle.</u>
- The side opposite the right angle is the hypotenuse, which is 9.
- The side opposite angle A is 3.
So we have the opposite of A and the hypotenuse.
The trigonometric ratio that relates opposite side to hypotenuse is SINE.

Since, we need angle A,
is A, opposite side is 3, and hypotenuse is 9, we substitute:

<em>To solve for the angle, we use our calculator and find the inverse sin of
:</em>

<em>Rounding to nearest tenth of a degree:</em>

B is the right choice.
Answer:y=4/3
y is directly proportional to x^2 is written as
introducing a constant,
y=kx^2
but from the question, when y=2 , x=3 . putting it in the formula to get the value of k

2=9k . <em>divi</em><em>ding</em><em> </em><em>throu</em><em>gh</em><em> </em><em>by</em><em> </em><em>9</em><em> </em><em>to</em><em> </em><em>get</em><em> </em><em>the</em><em> </em><em>valu</em><em>e</em><em> </em><em>of</em><em> </em><em>k</em>
<em>
</em>
<em>
</em>
<em>pu</em><em>tting</em><em> </em><em>it</em><em> </em><em>in</em><em> </em><em>the</em><em> </em><em>ge</em><em>neral</em><em> </em><em>expres</em><em>sion</em>
<em>
</em>
<em>the</em><em> </em><em>valu</em><em>e</em><em> </em><em>of</em><em> </em><em>y</em><em> </em><em>whe</em><em>n</em><em> </em><em>x</em><em>=</em><em>6</em>
<em>
</em>
<em>
</em>
<em>there</em><em>fore</em><em> </em><em>the</em><em> </em><em>valu</em><em>e</em><em> </em><em>of</em><em> </em><em>y</em><em> </em><em>when</em><em> </em><em>x</em><em>=</em><em>6</em><em> </em><em>is</em>
<em>4</em><em>/</em><em>3</em>