M<2 = 53
m<1 = 33
.......................
The number of different groups can be found by finding 9C3 (Using combinations)
We will find combinations from n = 9 to r = 3
Therefore, 9C3 = 9!/6!*3! = (9*8*7*6!)/(6!*3*2)
= 3*4*7
= 84 ways.
Answer:
The length of a is 3 units
And breadth of a is 1 units
The length of b is 9 units and the Breadth of b is 3 units.
Therefore, Ratio of their sides=1:3.
Therefore, Scale os 1:3
Answer:
ok thanks for the warning
Step-by-step explanation: