We have already seen how to approximate a function using its tangent line. This was the key idea in Euler’s
method. If we know the function value at some point (say f (a)) and the value of the derivative at the same
point (f
(a)) we can use these to find the tangent line, and then use the tangent line to approximate f (x)
for other points x. Of course, this approximation will only be good when x is relatively near a. The tangent
line approximation of f (x) for x near a is called the first degree Taylor Polynomial of f (x) and is:
f (x) ≈ f (a) + f
(a)(x − a)
Answer:

Step-by-step explanation:
we know that
If two figures are similar, then the ratio o its corresponding sides is proportional, and this ratio is called the scale factor
In this problem the corresponding sides are
12 units and 15 units
16 units and n units
therefore

Solve for n


Answer:
The exponential function that passes through (2,36) is:
.
Step-by-step explanation:
We are asked to find which function passes through the point (2,36).
i.e. we will put the input value '2' in the following given functions and check which gives the output value as '36'.
1)

now we put x=2.

hence option 1 is correct.
2)

Now we put x=2.

Hence, option 2 is incorrect.
3)

Now we put x=2

Hence, option 3 is incorrect.
4)

Now we put x=2.

Hence, option 4 is incorrect.
Hence, option 1) is correct.
i.e. The exponential function that passes through (2,36) is:

A) midpoint would be (-20+35)/2, (15-12)/2
= (15/2, 3/2)
B) Distance = sqrt((35--20)^2 +(-12-15)^2) = sqrt(3754) = 61.27 units
Answer:
-6 -6
Step-by-step explanation: