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zvonat [6]
3 years ago
7

Given: f(x) = 1/x+5 and g(x) = x - 2.

Mathematics
1 answer:
gavmur [86]3 years ago
7 0

Answer:

The restriction of the domain of f(g(x)) is that x cannot be 3.

Step-by-step explanation:

The first step to solve this question is finding the function, replacing the values. So

f(x) = \frac{1}{x+5}

g(x) = x - 2

f(g(x)) = f(x - 2) = \frac{1}{x - 2 + 5} = \frac{1}{x - 3}

The function is a fraction, which means that the restriction is that the denominator cannot be zero. So

x - 3 \neq 0

x \neq 3

The restriction of the domain of f(g(x)) is that x cannot be 3.

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Could you please look at this question?
MrMuchimi

Answer:

  a. see attached

  b. H(t) = 12 -10cos(πt/10)

  c. H(16) ≈ 8.91 m

Step-by-step explanation:

<h3>a.</h3>

The cosine function has its extreme (positive) value when its argument is 0, so we like to use that function for circular motion problems that have an extreme value at t=0. The midline of the function needs to be adjusted upward from 0 to a value that is 2 m more than the 10 m radius. The amplitude of the function will be the 10 m radius. The period of the function is 20 seconds, so the cosine function will be scaled so that one full period is completed at t=20. That is, the argument of the cosine will be 2π(t/20) = πt/10.

The function describing the height will be ...

  H(t) = 12 -10cos(πt/10)

The graph of it is attached.

__

<h3>b. </h3>

See part a.

__

<h3>c.</h3>

The wheel will reach the top of its travel after 1/2 of its period, or t=10. Then 6 seconds later is t=16.

  H(16) = 12 -10cos(π(16/10) = 12 -10cos(1.6π) ≈ 12 -10(0.309017) ≈ 8.90983

The height of the rider 6 seconds after passing the top will be about 8.91 m.

8 0
3 years ago
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Answer:

Step-by-step explanation:

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Step-by-step explanation:

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