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posledela
4 years ago
15

Calculate the amount of diluent required to make 100 mL of a 20% solution from a stock solution that is 80%.

Mathematics
1 answer:
Deffense [45]4 years ago
6 0

Answer:

C. 75mL

Step-by-step explanation:

Let's find the solution.

Let's consider that the stock solution is XmL.

Also let's consider than the amount of diluent required is Y.

Because we need to add YmL to the stock solution to obtain a 100mL solution, then:

X+Y=100 which can be written as:

X=100-Y (eq. 1)

Now, the stock solution is 80% which means:

0.8=n/X where n is the solute, which can be written as:

n=0.8X (eq. 2)

Because we are trying to make a 100mL of a 20% solution then:

0.2=n/100, using eq. 2 we have:

0.2=(0.8X)/100, using eq. 1 we have:

0.2=0.8*(100-Y)/100

0.2*100/0.8=100-Y

25=100-Y

Y=100-25=75

In conclusion, we need to add 75mL, so the answer is C.

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Step-by-step explanation:

The question in English is

Having organized a bingo has raised $1900. For the entrance of men $15 and women $10 and an attendance of 150 people has been reported. Determine the number of men and the number of women who participated in the bingo.

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x----> the number of men

y----> the number of women

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