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stiv31 [10]
3 years ago
9

Solve for sin3theta​

Mathematics
1 answer:
aniked [119]3 years ago
6 0

Answer:

 sin 3 θ  = 3 sin θ  - 4 sin³θ

Step-by-step explanation:

<u><em>Step(i):</em></u>-

Given    sin 3 θ  

            =  sin ( 2θ + θ )

apply trigonometric formula

       <em>  sin ( A + B) = sin A cos B + cos A sin B </em>

<em>         sin 2 A = 2 sin A cos B</em>

<em>         Cos 2 A = 1 - 2 sin² A </em>

<em>         cos ² A - sin ² A = 1</em>

<u><em>Step(ii):</em></u>-

    sin 3 θ  =     sin ( 2θ + θ )

               =  sin 2θ cosθ +  cos2θ sin θ

              = 2 sin θ cos θ cos θ +( 1 - 2 sin² θ )sin θ

              = 2 sin θ (cos² θ ) + sin θ- 2 sin³ θ

              = 2 sin θ ( 1- sin²θ) + sin θ- 2 sin³ θ

              = 2 sin θ - 2sin³θ +  sin θ- 2 sin³ θ

              = 3 sin θ  - 4 sin³θ

<u><em>Final answer</em></u> :-

 sin 3 θ  = 3 sin θ  - 4 sin³θ

                             

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