Angles A and B are complementary. If sin A = 4x + 10 and cos B = 2x + 16, what is the value of x? (

Mathematics

1 answer:

Aleks04 [339]2 years ago

5 0

Answer:

x is 10.66

Step-by-step explanation:

What are complementary angles?

They are angles that up to 90

So we have Sin A and Cos B

4x + 10+ 2x + 16= 90

collect like terms

6x+ 26= 90

6x= 90-26

6x= 64

x= 64/6

x= 10.66

Hence the value of x is 10.66

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=======================================================

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$\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = \lim_{x \to 3}\frac{(x-3)(x+2)}{x-3}\\\\\\\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = \lim_{x \to 3}(x+2)\\\\\\\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = 3+2\\\\\\\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = 5\\\\\\$