The number of students would not change between before the test and after the test. 3+8 and 4+7 both = 11 so finding out how many students would equal one ratio can then be used to find how many equal 3 and 8.
If 92 students are equal to 4 in the ratio, then 1 in the ratio is worth 23 students. This is important as then when you times 23 by 7 you find out how many students there are in the regular maths class, 161 students. Plussing these two together gives you a total of 253 students.
Using this 253 you can divide it by 11 to find out how much 1 number would be in the ratio, it equals 23. Using this you can then times 23 by both 3 and 8 to find the original class sizes, 3x23 = 69, and 23x8 = 184.
Making the origional class size of the advaced class 69 studnets, and the regular maths class size 184.
All you have to do is make 1 into a fraction 4/4+1/4 makes the 8 servings
find and equivilent fraction so 8/8+2/8= 8 servings half it 4/8+1/8= 4 servings so half a cup and an eighth of a cup or 5/8 of a cup hope this helped you have a great day!!
If this is for factoring, here’s how to do it.
7. 45n^2-5
-first, ask yourself what common factor does 45n^2 and 5 have? The answer is that they’re both divisible by 5
-next you want to expand this expression by dividing 5 out and rewriting it in multiplication. If you completely remove the 5 from the expression, you have created a new and different expression (which is not the goal). And so you will have: 5(9n^2-1)
-now we have to expand 9n^2-1. We know that (a-b)(a+b)=a^2-b^2; once you foil and multiply the expression, you’ll notice you cancelled ab with ab. So for this problem, you need to see what will make 9 and 1 once you square them(It’s 3 and 1).
-what you should have now is 5(3n-1)(3n+1). But ways check by foiling your answer to see if you end up with the same expression.
9. 45a^3-80a
what is similar about 45a^3 and 80a?
- both divisible by 5a
5a(9a^2-16)
what do you square to get 9 and 16
- 3 and 4
5a(3a-4)(3a+4)
When it comes to bigger numbers, use the quadratic formula to find the variables that‘ll be part of your factored answers(Remember to apply the opposite sign/operation when you insert the numbers you got from the formula - because the numbers from the formula are the solutions ex. If I got 3 and -4 from the formula, my factored expression would be (X-3)(X+4))
Answer: 168%
Step-by-step explanation:
to find how much the wolf population increased in 2016 (or the wolf population in 2017) , do 50 * 1.4.
doing this, you get 70. we multiple by 1.4 because 1 includes the original 50 with the .4 being the increase. you could also do 50 * .4 which is 20 and add that to the original if it's easier.
using our new number, we can multiple 70 by 1.2 (or by .2 and add that to 70, your choice) to get 84. we now have 84 in 2018
we now have to see how much it increased total (50-84)
do this by doing 84/50
this is 1.68
to check our work, do 1.68 & 50 and we get 84.
transfer this to percent (move the decimal over two spots), you get 168 percent.
0.9(y-4)=0.3(y-10)
0.9y-3.6=0.3y-3
0.9y-0.3y=-3+3.6
0.6y= 0.6
Y= 0.6y/0.6
Y= 1
The answer is 1.
Hope this helps!