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babunello [35]
3 years ago
12

Can you plz give me more of an anser

Mathematics
1 answer:
Aleks04 [339]3 years ago
6 0

Answer:

peepeepoopoo check

Step-by-step explanation:

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Perform the operation indicated, then place the answer in the proper location on the grid. The perimeter of a triangle is 7a - 1
vlada-n [284]

Answer: 4 a - 3 b

Step-by-step explanation:

Since, the perimeter of the triangle = sum of all the three side of the triangle.

Here, two sides of the triangle are 2a + b and a - 9b,

And, the perimeter of the triangle = 7 a - 11

Let third side = x

Therefore, 2 a + b + a - 9 b + x = 7 a - 11 b

⇒ 3 a - 8 b + x = 7 a - 11 b

⇒ x = 7 a - 11 b - 3 a + 8 b

⇒ x = 4 a - 3 b  ( by operating like terms)

3 0
3 years ago
How are the coordinates of the extreme value and the equation from part B in the form y=(x-h)^2-c related.
True [87]

The extreme value of y = (x - h)² - c is the vertex of the equation.

<h3>What are extreme values of a function?</h3>

The extreme values of a function are either the maximum or minimum values of the function.

<h3>The equation of a parabola in vertex form</h3>

The equation of a parabola in vertex form with vertex (h', k) is given by

y = a(x - h')² + k and its extreme values are

  • if a > 0  (h', k) is a minimum point and
  • if a < 0 (h', k) is a maximum point.

Since y = (x - h)² - c is the equation of a parabola in vertex form, comparing with y = a(x - h')² + k,

  • h = h'
  • -c = k and
  • a = 1.

So, the cooordinates of the vertex of y = (x - h)² - c is (h, -c).

Now, since a = 1 > 0, (h, -c) is a minimum point.

So, the extreme value of y = (x - h)² - c is the vertex of the equation.

Learn more about extreme value of a function here:

brainly.com/question/13464558

#SPJ1

4 0
2 years ago
Consider a manufacturing process that is producing hypodermic needles that will be used for blood donations. These needles need
Mars2501 [29]

Answer:

\text{Average diameter is 1.65 mm and we decide that it is not 1.65 mm.}                

Step-by-step explanation:

We are given the following in the question:

The needle size should not be too big and too small.

The diameter of the needle should be 1.65 mm.

We design the null and the alternate hypothesis

H_{0}: \mu = 1.65\text{ mm}\\H_A: \mu \neq 1.65\text{ mm}

Sample size, n = 35

Sample mean, \bar{x} = 1.64 mm

Sample standard deviation, s = 0.07 mm

Type I error:

  • It is the error of rejecting the null hypothesis when it is true.
  • It is also known as false positive error.
  • It is the rejecting of a true null hypothesis.

Thus, type I error in this study would mean we reject the null hypothesis that the average diameter is 1.65 mm but actually the average diameters of the needle is 1.65 mm.

Thus, average diameter is 1.65 mm and we decide that it is not 1.65 mm.

8 0
3 years ago
Read 2 more answers
please help i will make brainlest if you have correct answers please put your answers in order like the pictures like 1 2 3 4 5
Kruka [31]

1. 22/25

2. -1 1/4

3. -1 7/10

4. 1 5/6

5. 1 2/3

8 0
3 years ago
Read 2 more answers
Solve formula for B v= 1/3Bh
MaRussiya [10]

v = 1/3Bh

Divide both sides by h.

v/h = 1/3B

Multiply both sides by 3.

3v/h = B

\boxed {B = \frac{3v}{h} }

5 0
3 years ago
Read 2 more answers
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