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zloy xaker [14]

3 years ago

14

How do you find the x and y intercepts of x^2+x-2/x^2-3x-4?

1 answer:

melomori [17]3 years ago

3 0

First equal the equation to f(x) or y

f(x)= (x²+x-2)÷(x²-3x-4)

To find y-intercept, x coordinates have to be 0

f(0)=(0²+0-2)÷(0²-3(0)-4)
f(0)=-2/-4
f(0)=1/2 (y-intercept)

To find x-intercept, make y=0

0=(x²+x-2)÷(x²-3x-4)
0((x²-3x-4)=(x²+x-2)
0=x²+x-2
0=(x-1)(x+2)
x-1

x-1=0
x=1

x+2=0
x=-2

The x-intercepts would be 1, -2

Hope I helped :)

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What is the inverse of f(x) = sqft x+ 3

grin007 [14]

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Step-by-step explanation:

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