Question

How do you find the x and y intercepts of x^2+x-2/x^2-3x-4?

Answer 1

First equal the equation to f(x) or y 

f(x)= (x²+x-2)÷(x²-3x-4) 

To find y-intercept, x coordinates have to be 0 

f(0)=(0²+0-2)÷(0²-3(0)-4) 
f(0)=-2/-4
f(0)=1/2 (y-intercept)

To find x-intercept, make y=0 

0=(x²+x-2)÷(x²-3x-4) 
0((x²-3x-4)=(x²+x-2) 
0=x²+x-2 
0=(x-1)(x+2) 
x-1

x-1=0 
x=1 

x+2=0 
x=-2 

The x-intercepts would be 1, -2 

Hope I helped :)