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zloy xaker [14]
4 years ago
14

How do you find the x and y intercepts of x^2+x-2/x^2-3x-4?

Mathematics
1 answer:
melomori [17]4 years ago
3 0
First equal the equation to f(x) or y 

f(x)= (x²+x-2)÷(x²-3x-4) 

To find y-intercept, x coordinates have to be 0 

f(0)=(0²+0-2)÷(0²-3(0)-4) 
f(0)=-2/-4
f(0)=1/2 (y-intercept)

To find x-intercept, make y=0 

0=(x²+x-2)÷(x²-3x-4) 
0((x²-3x-4)=(x²+x-2) 
0=x²+x-2 
0=(x-1)(x+2) 
x-1

x-1=0 
x=1 

x+2=0 
x=-2 

The x-intercepts would be 1, -2 

Hope I helped :) 


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The perimeter of a square with side a = 7.2 cm is 28.8 cm. Yes there exists a direct proportional relationship between Side length and Perimeter of square

<h3><u>Solution:</u></h3>

Given that side of square "a" = 7.2 cm

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<em><u>The perimeter of square is given as:</u></em>

Perimeter of square = 4a

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Substituting the given value a = 7.2 cm in above formula, we get perimeter of square

Perimeter of square = 4(7.2) = 28.8 cm

<em><u>Are the perimeter of the square and the length of its side directly proportional quantities?</u></em>

\begin{array}{l}{\text { perimeter of square }=4 a=4 \times \text { length of side }} \\\\ {\frac{\text { perimeter of square }}{\text { length of side }}=4}\end{array}

The Perimeter is equal to a constant times the Side length, or the Perimeter divided by the Side length is equal to four. So this is definitely a proportional relationship between Side length and Perimeter.

Two values are said to be in direct proportion when an increase in one results in an increase in the other.

So when length of sides increases, perimeter also increases

Hence perimeter and length of side of square are directly propotional quantities

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